g(n)=1+5(n-1) Complete the recursive formula of g(n). {:[g(1)=◻],[g(n)=g(n-1)+]:}

Determine g(1): Determine the value of g(1) by substituting n=1 into the given formula. g(1) = 1 + 5(1 - 1) g(1) = 1 + 5(0) g(1) = 1 + 0 g(1) = 1Express in terms of g(n-1): Express g(n) in terms of g(n-1) to find the recursive formula. We know that g(n) = 1 + 5(n - 1). To express this in terms of g(n-1), we need to relate g(n) to g(n-1) using the given formula. g(n-1) = 1 + 5((n-1) - 1) g(n-1) = 1 + 5(n - 2) Now, we will add 5 to both sides to get g(n) from g(n-1). g(n) = g(n-1) + 5

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g(n)=1+5(n-1)
Complete the recursive formula of
g(n).

{:[g(1)=◻],[g(n)=g(n-1)+]:}

$g(n)=1+5(n-1)$ $\newline$ Complete the recursive formula of $g(n)$ . $\newline$ $g(1)=$ $\newline$ $g(n)=g(n-1)+$

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Algebra 2

Write a formula for an arithmetic sequence

Full solution

g(n)=1+5(n-1)

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Complete the recursive formula of

g(n)

\newline

g(1)=

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g(n)=g(n-1)+

Determine $g(1)$ : Determine the value of $g(1)$ by substituting $n=1$ into the given formula. $\newline$ $g(1) = 1 + 5(1 - 1)$ $\newline$ $g(1) = 1 + 5(0)$ $\newline$ $g(1) = 1 + 0$ $\newline$ $g(1) = 1$
Express in terms of $g(n-1)$ : Express $g(n)$ in terms of $g(n-1)$ to find the recursive formula. $\newline$ We know that $g(n) = 1 + 5(n - 1)$ . To express this in terms of $g(n-1)$ , we need to relate $g(n)$ to $g(n-1)$ using the given formula. $\newline$ $g(n-1) = 1 + 5((n-1) - 1)$ $\newline$ $g(n-1) = 1 + 5(n - 2)$ $\newline$ Now, we will add $5$ to both sides to get $g(n)$ from $g(n-1)$ . $\newline$ $g(n)$ $2$