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Fully simplify using only positive exponents.

(125x^(3)y^(2))/(x^(5)y^(3))
Answer:

Fully simplify using only positive exponents.\newline125x3y2x5y3 \frac{125 x^{3} y^{2}}{x^{5} y^{3}} \newlineAnswer:

Full solution

Q. Fully simplify using only positive exponents.\newline125x3y2x5y3 \frac{125 x^{3} y^{2}}{x^{5} y^{3}} \newlineAnswer:
  1. Identify Base Numbers: Identify the base numbers and their exponents in the numerator and the denominator.\newlineWe have 125x3y2125x^{3}y^{2} in the numerator and x5y3x^{5}y^{3} in the denominator.
  2. Simplify Numerical Part: Simplify the numerical part of the expression. 125125 is a perfect cube, as 125=53125 = 5^3. So, we can write 125125 as 535^3.
  3. Apply Quotient Rule: Apply the quotient rule for exponents.\newlineThe quotient rule states that am/an=amna^{m}/a^{n} = a^{m-n} when m > n.\newlineFor x3/x5x^{3}/x^{5}, we subtract the exponents: 35=23 - 5 = -2.\newlineFor y2/y3y^{2}/y^{3}, we subtract the exponents: 23=12 - 3 = -1.
  4. Write Expression with Exponents: Write the expression with the simplified exponents.\newlineWe have (53×x2×y1)(5^3 \times x^{-2} \times y^{-1}).
  5. Move Terms to Denominator: Since we want only positive exponents, we move the terms with negative exponents to the denominator.\newlineThis gives us 53/(x2y)5^3 / (x^2 \cdot y).
  6. Calculate Value of 535^3: Calculate the value of 535^3. \newline53=5×5×5=1255^3 = 5 \times 5 \times 5 = 125.
  7. Write Final Expression: Write the final simplified expression.\newlineThe final expression is 125x2y\frac{125}{x^2 \cdot y}.

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