Q. Fully simplify the expression below and write your answer as a single fraction.x2+7xx2−4⋅x2−9x+14x2−49Answer:
Factorize Numerators and Denominators: Factor the numerators and denominators where possible.The numerator of the first fraction, x2−4, is a difference of squares and can be factored as (x−2)(x+2).The denominator of the second fraction, x2−9x+14, can be factored as (x−7)(x−2) because it is a quadratic expression that factors neatly.The numerator of the second fraction, x2−49, is also a difference of squares and can be factored as (x−7)(x+7).
Rewrite with Factored Terms: Rewrite the expression with the factored terms.The expression becomes:x2+7x(x−2)(x+2)×(x−7)(x−2)(x−7)(x+7)
Cancel Common Factors: Cancel out the common factors.The (x−7) and (x−2) terms are present in both a numerator and a denominator, so they cancel each other out.The expression now simplifies to:x2+7xx+2×(x+7)
Multiply Remaining Terms: Multiply the remaining terms.Now we multiply the numerators and the denominators:Numerator: (x+2)×(x+7)Denominator: x2+7x
Expand Numerator: Expand the numerator.(x+2)×(x+7)=x2+7x+2x+14=x2+9x+14
Write Final Expression: Write the final simplified expression.The final expression is:(x2+9x+14)/(x2+7x)
More problems from Multiplication with rational exponents