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Fully simplify the expression below and write your answer as a single fraction.

(x^(3)-x)/(x^(2)+x)*(6x^(2)+6x-432)/(x^(2)-9x+8)
Answer:

Fully simplify the expression below and write your answer as a single fraction.\newlinex3xx2+x6x2+6x432x29x+8 \frac{x^{3}-x}{x^{2}+x} \cdot \frac{6 x^{2}+6 x-432}{x^{2}-9 x+8} \newlineAnswer:

Full solution

Q. Fully simplify the expression below and write your answer as a single fraction.\newlinex3xx2+x6x2+6x432x29x+8 \frac{x^{3}-x}{x^{2}+x} \cdot \frac{6 x^{2}+6 x-432}{x^{2}-9 x+8} \newlineAnswer:
  1. Factor Numerator and Denominator: Factor the numerator and denominator of both fractions where possible.\newlineThe first fraction's numerator can be factored by recognizing it as a difference of squares:\newlinex3x=x(x21)=x(x+1)(x1)x^3 - x = x(x^2 - 1) = x(x + 1)(x - 1)\newlineThe first fraction's denominator is already factored:\newlinex2+x=x(x+1)x^2 + x = x(x + 1)\newlineThe second fraction's numerator does not factor nicely, but we can factor out a common factor of 66:\newline6x2+6x432=6(x2+x72)6x^2 + 6x - 432 = 6(x^2 + x - 72)\newlineThe second fraction's denominator can be factored as a quadratic:\newlinex29x+8=(x1)(x8)x^2 - 9x + 8 = (x - 1)(x - 8)
  2. Rewrite with Factored Terms: Rewrite the expression with the factored terms.\newlineNow we have:\newlinex(x+1)(x1)x(x+1)\frac{x(x + 1)(x - 1)}{x(x + 1)} * 6(x2+x72)(x1)(x8)\frac{6(x^2 + x - 72)}{(x - 1)(x - 8)}
  3. Cancel Common Factors: Cancel out the common factors in the numerator and denominator.\newlineIn the first fraction, xx and (x+1)(x + 1) are common to both the numerator and the denominator, so they cancel out. In the second fraction, (x1)(x - 1) is common to both the numerator and the denominator, so it cancels out as well.\newlineAfter canceling, we have:\newline(x1)×6(x2+x72)(x8)(x - 1) \times \frac{6(x^2 + x - 72)}{(x - 8)}
  4. Expand Remaining Terms: Expand the remaining terms in the numerator of the second fraction.\newlineWe need to distribute the 66 to each term inside the parentheses:\newline6(x2+x72)=6x2+6x4326(x^2 + x - 72) = 6x^2 + 6x - 432\newlineNow the expression looks like this:\newline(x1)((6x2+6x432)/(x8))(x - 1) * ((6x^2 + 6x - 432) / (x - 8))
  5. Multiply Remaining Terms: Multiply the remaining terms in the numerator.\newlineWe multiply (x1)(x - 1) by each term in the numerator of the second fraction:\newline(x1)(6x2+6x432)=6x3+6x26x6x26x+432(x - 1)(6x^2 + 6x - 432) = 6x^3 + 6x^2 - 6x - 6x^2 - 6x + 432
  6. Combine Like Terms: Combine like terms in the numerator.\newlineAfter distributing, we combine the like terms:\newline6x3+6x26x6x26x+432=6x312x+4326x^3 + 6x^2 - 6x - 6x^2 - 6x + 432 = 6x^3 - 12x + 432\newlineNow the expression is:\newline(6x312x+432)/(x8)(6x^3 - 12x + 432) / (x - 8)
  7. Check for Further Simplification: Check for any further simplification.\newlineWe can factor out a 66 from the numerator to see if there is any further simplification:\newline6x312x+432=6(x32x+72)6x^3 - 12x + 432 = 6(x^3 - 2x + 72)\newlineHowever, the expression x32x+72x^3 - 2x + 72 does not factor nicely, and there are no common factors with the denominator (x8)(x - 8). So, this is the final simplified form.

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