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Fully simplify the expression below and write your answer as a single fraction.

(x^(2)+5x)/(x^(2)+4x+3)*(4x^(2)-4)/(6x^(2)+24 x-30)
Answer:

Fully simplify the expression below and write your answer as a single fraction.\newlinex2+5xx2+4x+34x246x2+24x30 \frac{x^{2}+5 x}{x^{2}+4 x+3} \cdot \frac{4 x^{2}-4}{6 x^{2}+24 x-30} \newlineAnswer:

Full solution

Q. Fully simplify the expression below and write your answer as a single fraction.\newlinex2+5xx2+4x+34x246x2+24x30 \frac{x^{2}+5 x}{x^{2}+4 x+3} \cdot \frac{4 x^{2}-4}{6 x^{2}+24 x-30} \newlineAnswer:
  1. Factorize fractions: Factor the numerator and denominator of both fractions where possible.\newlineThe first fraction is (x2+5x)/(x2+4x+3)(x^2 + 5x) / (x^2 + 4x + 3). We can factor the numerator by taking out the common factor xx, and the denominator can be factored as a sum of squares.\newlinex(x+5)/((x+1)(x+3))x(x + 5) / ((x + 1)(x + 3))\newlineThe second fraction is (4x24)/(6x2+24x30)(4x^2 - 4) / (6x^2 + 24x - 30). We can factor out the common factor 44 in the numerator and factor the denominator.\newline4(x21)/(6(x2+4x5))4(x^2 - 1) / (6(x^2 + 4x - 5))\newlineNow, notice that x21x^2 - 1 is a difference of squares and can be factored further.\newline4((x+1)(x1))/(6(x2+4x5))4((x + 1)(x - 1)) / (6(x^2 + 4x - 5))
  2. Factorize second fraction: Factor the denominator of the second fraction.\newlineWe need to factor 6(x2+4x5)6(x^2 + 4x - 5). To do this, we look for two numbers that multiply to 30-30 (6×56 \times -5) and add to 44. These numbers are 66 and 5-5.\newlineSo, the factored form of the denominator is:\newline6((x+6)(x5))6((x + 6)(x - 5))\newlineNow we can rewrite the second fraction as:\newline4((x+1)(x1))6(x+6)(x5)\frac{4((x + 1)(x - 1))}{6(x + 6)(x - 5)}
  3. Multiply fractions: Combine the two fractions by multiplying them.\newlinex(x+5)(x+1)(x+3)\frac{x(x + 5)}{(x + 1)(x + 3)} * 4((x+1)(x1))6(x+6)(x5)\frac{4((x + 1)(x - 1))}{6(x + 6)(x - 5)}\newlineTo multiply fractions, we multiply the numerators together and the denominators together.\newlinex(x+5)4((x+1)(x1))((x+1)(x+3))(6(x+6)(x5))\frac{x(x + 5) * 4((x + 1)(x - 1))}{((x + 1)(x + 3)) * (6(x + 6)(x - 5))}
  4. Cancel common factors: Cancel out common factors.\newlineWe can cancel out the (x+1)(x + 1) term that appears in both a numerator and a denominator.\newlinex(x+5)4(x1)(x+3)(6(x+6)(x5))\frac{x(x + 5) \cdot 4(x - 1)}{(x + 3) \cdot (6(x + 6)(x - 5))}
  5. Simplify expression: Simplify the expression.\newlineNow we multiply out the remaining terms.\newline(4x2+20x)×(4(x1))/((x+3)×(6(x+6)(x5)))(4x^2 + 20x) \times (4(x - 1)) / ((x + 3) \times (6(x + 6)(x - 5)))\newlineWe can distribute the 44 in the numerator:\newline(16x216x)/((x+3)×(6(x+6)(x5)))(16x^2 - 16x) / ((x + 3) \times (6(x + 6)(x - 5)))
  6. Multiply denominator terms: Simplify the expression further.\newlineWe can now multiply the terms in the denominator:\newline(16x216x)/(6(x2+6x5x30))(16x^2 - 16x) / (6(x^2 + 6x - 5x - 30))\newlineSimplify the terms in the denominator:\newline(16x216x)/(6(x2+x30))(16x^2 - 16x) / (6(x^2 + x - 30))
  7. Reduce common factors: Simplify the expression by reducing common factors.\newlineWe can divide both the numerator and the denominator by 22:\newline8x28x3(x2+x30)\frac{8x^2 - 8x}{3(x^2 + x - 30)}
  8. Check for further simplification: Check if the expression can be simplified further.\newlineThe numerator and denominator do not have any common factors left, and the denominator cannot be factored in a way that would cancel out with the numerator. Therefore, the expression is fully simplified.

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