Fully simplify. (3x^(4)+y^(5))^(2) Answer:

Apply Binomial Expansion: Apply the binomial expansion to the expression (3x^(4)+y^(5))^(2). When we square a binomial, we use the formula (a+b)^2 = a^2 + 2ab + b^2, where a is the first term and b is the second term. In this case, a = 3x^4 and b = y^5.Square First Term: Square the first term (3x^4)^2. (3x^4)^2 = 3^2 * (x^4)^2 = 9x^8Multiply and Double: Multiply the two terms together and double the result, 2 * (3x^4) * (y^5). 2 * (3x^4) * (y^5) = 2 * 3 * x^4 * y^5 = 6x^4y^5Square Second Term: Square the second term (y^5)^2. (y^5)^2 = (y^5) * (y^5) = y^10Combine Results: Combine the results from steps 2, 3, and 4 to get the final simplified expression. 9x^8 + 6x^4y^5 + y^10

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Fully simplify.

(3x^(4)+y^(5))^(2)
Answer:

Fully simplify. $\newline$ $\left(3 x^{4}+y^{5}\right)^{2}$ $\newline$ Answer:

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Algebra 2

Evaluate rational exponents

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Q. Fully simplify.

\newline

\left(3 x^{4}+y^{5}\right)^{2}

\newline

Answer:

Apply Binomial Expansion: Apply the binomial expansion to the expression $(3x^{4}+y^{5})^{2}$ . When we square a binomial, we use the formula $(a+b)^{2} = a^{2} + 2ab + b^{2}$ , where $a$ is the first term and $b$ is the second term. In this case, $a = 3x^{4}$ and $b = y^{5}$ .
Square First Term: Square the first term $(3x^4)^2$ . $(3x^4)^2 = 3^2 \times (x^4)^2 = 9x^8$
Multiply and Double: Multiply the two terms together and double the result, $2 \times (3x^4) \times (y^5)$ . $\newline$ $2 \times (3x^4) \times (y^5) = 2 \times 3 \times x^4 \times y^5 = 6x^4y^5$
Square Second Term: Square the second term $(y^5)^2$ . $(y^5)^2 = (y^5) \times (y^5) = y^{10}$
Combine Results: Combine the results from steps $2$ , $3$ , and $4$ to get the final simplified expression. $\newline$ $9x^8 + 6x^4y^5 + y^{10}$