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Francisco is saving money and plans on making quarterly contributions into an account earning a quarterly interest rate of 
1.45%. If Francisco would like to end up with 
$48,000 after 12 years, how much does he need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Francisco is saving money and plans on making quarterly contributions into an account earning a quarterly interest rate of 1.45% 1.45 \% . If Francisco would like to end up with $48,000 \$ 48,000 after 1212 years, how much does he need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Francisco is saving money and plans on making quarterly contributions into an account earning a quarterly interest rate of 1.45% 1.45 \% . If Francisco would like to end up with $48,000 \$ 48,000 after 1212 years, how much does he need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineAA (future value of the account) = $48,000\$48,000\newlineii (interest rate per period) = 1.45%1.45\% or 0.01450.0145 when converted to decimal\newlinenn (number of periods) = 1212 years * 44 quarters/year = 4848 quarters\newlineWe will use these values in the formula provided.
  2. Plug Values into Formula: Plug the given values into the formula to solve for dd (the amount invested at the end of each period).\newlineThe formula is A=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right).\newlineWe have A=$48,000A = \$48,000, i=0.0145i = 0.0145, and n=48n = 48.
  3. Calculate (1+i)n(1 + i)^n: Calculate the value inside the parentheses, (1+i)n(1 + i)^n.(1+i)n=(1+0.0145)48(1 + i)^n = (1 + 0.0145)^{48}Use a calculator to find the value.(1+0.0145)481.9996(1 + 0.0145)^{48} \approx 1.9996
  4. Calculate ((1+i)n1)((1 + i)^n - 1): Calculate the numerator of the fraction, ((1+i)n1)((1 + i)^n - 1).
    ((1+i)n1)=1.99961((1 + i)^n - 1) = 1.9996 - 1
    ((1+i)n1)0.9996((1 + i)^n - 1) \approx 0.9996
  5. Calculate Entire Fraction: Calculate the entire fraction, (1+i)n1i\frac{(1 + i)^n - 1}{i}.(1+i)n1i=0.99960.0145\frac{(1 + i)^n - 1}{i} = \frac{0.9996}{0.0145}(1+i)n1i68.9379\frac{(1 + i)^n - 1}{i} \approx 68.9379
  6. Solve for d: Solve for d using the formula A=d×((1+i)n1)/iA = d \times \left(\left(1 + i\right)^n - 1\right) / i.
    $48,000=d×68.9379\$48,000 = d \times 68.9379
    Now, divide both sides by 68.937968.9379 to solve for d.
    d=$48,000/68.9379d = \$48,000 / 68.9379
    d$696.15d \approx \$696.15
  7. Round to Nearest Dollar: Round the result to the nearest dollar. d$696.15d \approx \$696.15 rounds to $696\$696.

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