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For the rotation 
1025^(@), find the coterminal angle from 
0^(@) <= theta < 360^(@), the quadrant, and the reference angle.
The coterminal angle is 
◻^(@), which lies in Quadrant 
◻, with a reference angle of 
◻^(@).

For the rotation 1025 1025^{\circ} , find the coterminal angle from 0^{\circ} \leq \theta<360^{\circ} , the quadrant, and the reference angle.\newlineThe coterminal angle is \square^{\circ} , which lies in Quadrant \square , with a reference angle of \square^{\circ} .

Full solution

Q. For the rotation 1025 1025^{\circ} , find the coterminal angle from 0θ<360 0^{\circ} \leq \theta<360^{\circ} , the quadrant, and the reference angle.\newlineThe coterminal angle is \square^{\circ} , which lies in Quadrant \square , with a reference angle of \square^{\circ} .
  1. Subtract multiples of 360360: To find the coterminal angle between 00 and 360360 degrees, subtract multiples of 360360 from 10251025 until the result is within the desired range.\newline1025360=6651025 - 360 = 665
  2. Continue subtracting 360360 degrees: Continue subtracting 360360 degrees:\newline665360=305665 - 360 = 305\newlineNow, 305305 is between 00 and 360360 degrees.
  3. Coterminal angle determination: The coterminal angle is 305305 degrees.\newlineTo determine the quadrant, note that 305305 degrees is more than 270270 but less than 360360, so it's in Quadrant IV.
  4. Quadrant identification: To find the reference angle, subtract 305305 from 360360 because it's in the fourth quadrant.\newline360305=55360 - 305 = 55\newlineThe reference angle is 5555 degrees.

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