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For the function 
f(x)=(-3)/(1+3x), find 
f^(-1)(x).
Answer: 
f^(-1)(x)=

For the function f(x)=31+3x f(x)=\frac{-3}{1+3 x} , find f1(x) f^{-1}(x) .\newlineAnswer: f1(x)= f^{-1}(x)=

Full solution

Q. For the function f(x)=31+3x f(x)=\frac{-3}{1+3 x} , find f1(x) f^{-1}(x) .\newlineAnswer: f1(x)= f^{-1}(x)=
  1. Replace with y: To find the inverse function, f1(x)f^{-1}(x), we need to switch the roles of xx and yy in the original function and then solve for yy.
    Let's start by replacing f(x)f(x) with yy:
    y=31+3xy = \frac{-3}{1+3x}
  2. Switch x and y: Now, switch x and y to find the inverse: x=31+3yx = \frac{-3}{1+3y}
  3. Multiply by (1+3y)(1+3y): Next, we need to solve for yy. Start by multiplying both sides of the equation by (1+3y)(1+3y) to get rid of the fraction:\newlinex(1+3y)=3x \cdot (1+3y) = -3
  4. Distribute xx: Distribute xx on the left side of the equation:\newlinex+3xy=3x + 3xy = -3
  5. Isolate terms with y: Now, isolate terms with y on one side:\newline3xy=3x3xy = -3 - x
  6. Factor out yy: Factor out yy from the left side:\newliney(3x)=3xy(3x) = -3 - x
  7. Divide by 3x3x: Divide both sides by 3x3x to solve for yy:y=3x3xy = \frac{-3 - x}{3x}
  8. Split the fraction: Simplify the expression for yy by splitting the fraction: y=1x33xy = -\frac{1}{x} - \frac{3}{3x}
  9. Simplify the expression: Simplify the second term of the expression: y=1x1xy = -\frac{1}{x} - \frac{1}{x}
  10. Combine the terms: Combine the terms: y=2xy = -\frac{2}{x}
  11. Write the inverse function: Now that we have solved for yy, we can write the inverse function: f1(x)=2xf^{-1}(x) = -\frac{2}{x}

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