Q. For the following equation, evaluate f′(1).f(x)=5x5+2x3+xAnswer:
Identify Function: We need to find the derivative of the function f(x)=5x5+2x3+x with respect to x. This will give us f′(x), which we can then evaluate at x=1.
Apply Power Rule: Differentiate the function term by term using the power rule, which states that the derivative of xn with respect to x is n∗x(n−1).f′(x)=dxd[5x5]+dxd[2x3]+dxd[x]f′(x)=5⋅5x(5−1)+2⋅3x(3−1)+1⋅x(1−1)f′(x)=25x4+6x2+1
Evaluate at x=1: Evaluate the derivative at x=1. f′(1)=25(1)4+6(1)2+1 f′(1)=25+6+1 f′(1)=32
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