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For the following equation, evaluate 
f^(')(1).

f(x)=5x^(5)+2x^(3)+x
Answer:

For the following equation, evaluate f(1) f^{\prime}(1) .\newlinef(x)=5x5+2x3+x f(x)=5 x^{5}+2 x^{3}+x \newlineAnswer:

Full solution

Q. For the following equation, evaluate f(1) f^{\prime}(1) .\newlinef(x)=5x5+2x3+x f(x)=5 x^{5}+2 x^{3}+x \newlineAnswer:
  1. Identify Function: We need to find the derivative of the function f(x)=5x5+2x3+xf(x) = 5x^5 + 2x^3 + x with respect to xx. This will give us f(x)f'(x), which we can then evaluate at x=1x = 1.
  2. Apply Power Rule: Differentiate the function term by term using the power rule, which states that the derivative of xnx^n with respect to xx is nx(n1)n*x^{(n-1)}.\newlinef(x)=ddx[5x5]+ddx[2x3]+ddx[x]f'(x) = \frac{d}{dx} [5x^5] + \frac{d}{dx} [2x^3] + \frac{d}{dx} [x]\newlinef(x)=55x(51)+23x(31)+1x(11)f'(x) = 5 \cdot 5x^{(5-1)} + 2 \cdot 3x^{(3-1)} + 1 \cdot x^{(1-1)}\newlinef(x)=25x4+6x2+1f'(x) = 25x^4 + 6x^2 + 1
  3. Evaluate at x=1x = 1: Evaluate the derivative at x=1x = 1.
    f(1)=25(1)4+6(1)2+1f'(1) = 25(1)^4 + 6(1)^2 + 1
    f(1)=25+6+1f'(1) = 25 + 6 + 1
    f(1)=32f'(1) = 32

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