Find the zeros of the function f(x)=x^(2)+7.8 x+12.3. Round values to the nearest hundredth (if necessary). Answer: x=

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Find the zeros of the function  f(x)=x^(2)+7.8 x+12.3. Round values to the nearest hundredth (if necessary). Answer:  x=

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Identify equation type: Identify the type of equation and the method to find its zeros. The given function is a quadratic equation of the form f(x) = ax^2 + bx + c. To find the zeros of the function, we can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a), where a, b, and c are the coefficients of the quadratic equation.Apply quadratic formula: Apply the quadratic formula to the given function. For the function f(x) = x^2 + 7.8x + 12.3, the coefficients are a = 1, b = 7.8, and c = 12.3. Plugging these values into the quadratic formula gives us: x = [-7.8 ± sqrt(7.8^2 - 4*1*12.3)] / (2*1)Calculate discriminant: Calculate the discriminant (the part under the square root in the quadratic formula). The discriminant is b^2 - 4ac, so we calculate: 7.8^2 - 4*1*12.3 = 60.84 - 49.2 = 11.64Calculate square root: Calculate the square root of the discriminant. sqrt(11.64) ≈ 3.41Calculate possible values: Calculate the two possible values for x using the quadratic formula. x = [-7.8 ± 3.41] / 2 This gives us two solutions: x1 = (-7.8 + 3.41) / 2 x2 = (-7.8 - 3.41) / 2Solve for x1 and x2: Solve for x1 and x2. x1 = (-7.8 + 3.41) / 2 ≈ -2.195 x2 = (-7.8 - 3.41) / 2 ≈ -5.605Round solutions: Round the solutions to the nearest hundredth. x1 ≈ -2.20 x2 ≈ -5.61

Find the zeros of the function $f(x)=x^{2}+7.8 x+12.3$ . Round values to the nearest hundredth (if necessary). $\newline$ Answer: $x=$

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Find the zeros of the function f(x)=x2+7.8x+12.3 f(x)=x^{2}+7.8 x+12.3 f(x)=x2+7.8x+12.3. Round values to the nearest hundredth (if necessary).\newlineAnswer: x= x= x=

Find the zeros of the function $f(x)=x^{2}+7.8 x+12.3$ . Round values to the nearest hundredth (if necessary). $\newline$ Answer: $x=$