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Find the zeros of the function 
f(x)=x^(2)+2x-2. Round values to the nearest hundredth (if necessary).
Answer: 
x=

Find the zeros of the function f(x)=x2+2x2 f(x)=x^{2}+2 x-2 . Round values to the nearest hundredth (if necessary).\newlineAnswer: x= x=

Full solution

Q. Find the zeros of the function f(x)=x2+2x2 f(x)=x^{2}+2 x-2 . Round values to the nearest hundredth (if necessary).\newlineAnswer: x= x=
  1. Set up equation: Set up the equation to find the zeros of the function.\newlineTo find the zeros of the function f(x)=x2+2x2f(x) = x^2 + 2x - 2, we need to solve the equation f(x)=0f(x) = 0. This gives us the quadratic equation x2+2x2=0x^2 + 2x - 2 = 0.
  2. Use quadratic formula: Use the quadratic formula to solve for xx. The quadratic formula is x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients from the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0. In our case, a=1a = 1, b=2b = 2, and c=2c = -2.
  3. Calculate discriminant: Calculate the discriminant.\newlineThe discriminant is the part of the quadratic formula under the square root, b24acb^2 - 4ac. For our equation, it is 224(1)(2)=4+8=122^2 - 4(1)(-2) = 4 + 8 = 12.
  4. Apply to formula: Apply the discriminant to the quadratic formula.\newlineNow we can plug the values into the quadratic formula: x=2±1221x = \frac{-2 \pm \sqrt{12}}{2 \cdot 1}. This simplifies to x=2±122x = \frac{-2 \pm \sqrt{12}}{2}.
  5. Simplify square root: Simplify the square root.\newlineThe square root of 1212 can be simplified to 232\sqrt{3}. So the equation becomes x=2±232x = \frac{-2 \pm 2\sqrt{3}}{2}.
  6. Simplify equation: Simplify the equation further.\newlineWe can divide both terms in the numerator by 22, which gives us x=1±3x = -1 \pm \sqrt{3}.
  7. Calculate decimal values: Calculate the approximate decimal values.\newlineThe square root of 33 is approximately 1.7321.732. So we have two solutions: x=1+1.732x = -1 + 1.732 and x=11.732x = -1 - 1.732.
  8. Round solutions: Round the solutions to the nearest hundredth.\newlineThe first solution is x0.732x \approx 0.732 and the second solution is x2.732x \approx -2.732 when rounded to the nearest hundredth.

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