Q. Find the zeros of the function f(x)=x2+2x−2. Round values to the nearest hundredth (if necessary).Answer: x=
Set up equation: Set up the equation to find the zeros of the function.To find the zeros of the function f(x)=x2+2x−2, we need to solve the equation f(x)=0. This gives us the quadratic equationx2+2x−2=0.
Use quadratic formula: Use the quadratic formula to solve for x. The quadratic formula is x=2a−b±b2−4ac, where a, b, and c are the coefficients from the quadratic equation ax2+bx+c=0. In our case, a=1, b=2, and c=−2.
Calculate discriminant: Calculate the discriminant.The discriminant is the part of the quadratic formula under the square root, b2−4ac. For our equation, it is 22−4(1)(−2)=4+8=12.
Apply to formula: Apply the discriminant to the quadratic formula.Now we can plug the values into the quadratic formula: x=2⋅1−2±12. This simplifies to x=2−2±12.
Simplify square root: Simplify the square root.The square root of 12 can be simplified to 23. So the equation becomes x=2−2±23.
Simplify equation: Simplify the equation further.We can divide both terms in the numerator by 2, which gives us x=−1±3.
Calculate decimal values: Calculate the approximate decimal values.The square root of 3 is approximately 1.732. So we have two solutions: x=−1+1.732 and x=−1−1.732.
Round solutions: Round the solutions to the nearest hundredth.The first solution is x≈0.732 and the second solution is x≈−2.732 when rounded to the nearest hundredth.
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