Q. Find the zeros of the function f(x)=2x2−8.4x+5.2. Round values to the nearest hundredth (if necessary).Answer: x=
Identify Equation Type: Identify the type of equation and the method to find its zeros.The given function f(x)=2x2−8.4x+5.2 is a quadratic equation. To find the zeros of a quadratic equation, we can use the quadratic formula: x=2a−b±b2−4ac, where a, b, and c are the coefficients of the equation ax2+bx+c=0.
Apply Quadratic Formula: Apply the quadratic formula to the given equation.For the equation f(x)=2x2−8.4x+5.2, the coefficients are a=2, b=−8.4, and c=5.2. Plugging these values into the quadratic formula gives us:x=2⋅2−(−8.4)±(−8.4)2−4⋅2⋅5.2x=48.4±70.56−41.6x=48.4±28.96
Simplify Expression and Calculate: Simplify the expression under the square root and calculate the zeros.x=48.4±28.96x=48.4±5.38Now we have two possible solutions for x:x1=48.4+5.38x2=48.4−5.38
Calculate First Zero: Calculate the first zero x1.x1=48.4+5.38x1=413.78x1=3.445Rounded to the nearest hundredth, x1≈3.45
Calculate Second Zero: Calculate the second zero (x2).x2=(8.4−5.38)/4x2=3.02/4x2=0.755Rounded to the nearest hundredth, x2≈0.76
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