Q. Find the zeros of the function f(x)=2x2+16.2x+28. Round values to the nearest hundredth (if necessary).Answer: x=
Identify Equation Type: Identify the type of equation and the method to find its zeros.The given function f(x)=2x2+16.2x+28 is a quadratic equation. To find the zeros of a quadratic equation, we can use the quadratic formulax=2a−b±b2−4ac, where a, b, and c are the coefficients of the terms x2, x, and the constant term, respectively.
Apply Quadratic Formula: Apply the quadratic formula to find the zeros of the function.For the given function, a=2, b=16.2, and c=28. Plugging these values into the quadratic formula gives us:x=2⋅2−16.2±(16.2)2−4⋅2⋅28
Calculate Discriminant: Calculate the discriminant (the part under the square root in the quadratic formula).The discriminant is b2−4ac, so we calculate:(16.2)2−4×2×28=262.44−224=38.44
Calculate Square Root: Calculate the square root of the discriminant. 38.44≈6.20
Calculate Possible Values: Calculate the two possible values for x using the quadratic formula.x=4−16.2±6.20We have two solutions: one with the plus sign and one with the minus sign.
Calculate First Zero: Calculate the first zero using the plus sign in the quadratic formula.x=4−16.2+6.20x=4−10x=−2.5
Calculate Second Zero: Calculate the second zero using the minus sign in the quadratic formula.x=4−16.2−6.20x=4−22.4x=−5.6
Round Zeros: Round the zeros to the nearest hundredth if necessary.The zeros are already at the nearest hundredth, so we have:x≈−2.50 and x≈−5.60
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