Q. Find the zeros of the function f(x)=2x2−13.1x+18. Round values to the nearest hundredth (if necessary).Answer: x=
Calculate Discriminant: To find the zeros of the function f(x)=2x2−13.1x+18, we need to solve the quadratic equation2x2−13.1x+18=0. We can use the quadratic formulax=2a−b±b2−4ac, where a=2, b=−13.1, and c=18.
Apply Quadratic Formula: First, calculate the discriminant, which is b2−4ac. Here, b=−13.1, a=2, and c=18. So, the discriminant is (−13.1)2−4×2×18.
Calculate Solutions: Calculating the discriminant gives us 171.61−144=27.61.
Calculate Square Root: Now, we can apply the quadratic formula. The two solutions for x will be:x=2×2−(−13.1)±27.61x=413.1±27.61
Find Final Solutions: Calculating the square root of the discriminant, we get 27.61=5.26.
Round to Nearest Hundredth: Now we have two possible solutions for x:x=413.1+5.26 and x=413.1−5.26
Round to Nearest Hundredth: Now we have two possible solutions for x:x=413.1+5.26 and x=413.1−5.26Calculating these, we get:x=418.36 and x=47.84x=4.59 and x=1.96
Round to Nearest Hundredth: Now we have two possible solutions for x:x=413.1+5.26 and x=413.1−5.26Calculating these, we get:x=418.36 and x=47.84x=4.59 and x=1.96Rounding these values to the nearest hundredth, we get:x≈4.59 and x≈1.96
More problems from Find trigonometric functions using a calculator