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Find the yy-intercept of the parabola y=x2+3110y = x^2 + \frac{31}{10}. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____

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Q. Find the yy-intercept of the parabola y=x2+3110y = x^2 + \frac{31}{10}. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____
  1. Evaluate y-intercept: To find the y-intercept of the parabola, we need to evaluate the equation y=x2+3110y = x^2 + \frac{31}{10} when x=0x = 0.
  2. Substitute x=0x=0: Substitute x=0x = 0 into the equation to find the y-intercept.y=(0)2+3110y = (0)^2 + \frac{31}{10}y=0+3110y = 0 + \frac{31}{10}y=3110y = \frac{31}{10}
  3. Calculate y-intercept: The y-intercept of the parabola y=x2+3110y = x^2 + \frac{31}{10} is the point (0,3110)(0, \frac{31}{10}).

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