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Find the yy-intercept of the parabola y=x2−10y = x^2 - 10. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____

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Q. Find the yy-intercept of the parabola y=x2−10y = x^2 - 10. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____
  1. Find y-intercept: To find the y-intercept of the parabola, we need to determine the value of yy when x=0x = 0.
  2. Substitute x=0x=0: Substitute x=0x = 0 into the equation y=x2−10y = x^2 − 10.\newliney=(0)2−10y = (0)^2 − 10\newliney=0−10y = 0 − 10\newliney=−10y = -10
  3. Determine yy value: The yy-intercept of the parabola is the point where the parabola crosses the yy-axis, which occurs at (0,y)(0, y). Since we found y=−10y = -10 when x=0x = 0, the yy-intercept is at (0,−10)(0, -10).

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