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Find the volume of a right circular cone that has a height of 
14.2m and a base with a radius of 
16m. Round your answer to the nearest tenth of a cubic meter.
Answer: 
m^(3)

Find the volume of a right circular cone that has a height of 14.2 m 14.2 \mathrm{~m} and a base with a radius of 16 m 16 \mathrm{~m} . Round your answer to the nearest tenth of a cubic meter.\newlineAnswer: m3 \mathrm{m}^{3}

Full solution

Q. Find the volume of a right circular cone that has a height of 14.2 m 14.2 \mathrm{~m} and a base with a radius of 16 m 16 \mathrm{~m} . Round your answer to the nearest tenth of a cubic meter.\newlineAnswer: m3 \mathrm{m}^{3}
  1. Plug values into formula: The formula to calculate the volume of a right circular cone is V=13πr2hV = \frac{1}{3}\pi r^2 h, where rr is the radius of the base and hh is the height of the cone. We are given that the radius rr is 1616 meters and the height hh is 14.214.2 meters. Let's plug these values into the formula.
  2. Calculate base area: First, calculate the area of the base (which is a circle) using the formula A=πr2A = \pi r^2. The radius rr is 1616 meters, so A=π(16)2A = \pi(16)^2.
  3. Compute base area: Now, compute the area of the base: A=π(16)2=π(256)A = \pi(16)^2 = \pi(256). We will use the value of π\pi as approximately 3.141593.14159 for this calculation.
  4. Calculate cone volume: Next, calculate the volume of the cone using the volume formula V=13πr2hV = \frac{1}{3}\pi r^2 h. We already have the area of the base A=π(256)A = \pi(256), so we can substitute this into the formula and multiply by the height hh, which is 14.214.2 meters: V=13π(256)(14.2)V = \frac{1}{3}\pi(256)(14.2).
  5. Perform multiplication: Perform the multiplication to find the volume: V=(13)×3.14159×256×14.2V = (\frac{1}{3}) \times 3.14159 \times 256 \times 14.2. First, calculate 256×14.2=3635.2256 \times 14.2 = 3635.2.
  6. Multiply by pi: Now, multiply this result by π\pi: 3635.2×3.1415911426.53635.2 \times 3.14159 \approx 11426.5.
  7. Divide by 33: Finally, divide by 33 to get the volume of the cone: V11426.5/33808.8333V \approx 11426.5 / 3 \approx 3808.8333 cubic meters.
  8. Round to nearest tenth: Round the volume to the nearest tenth of a cubic meter: V3808.8V \approx 3808.8 m3\text{m}^3.

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