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Find the volume of a right circular cone that has a height of 2.1 in and a base with a diameter of 4.8 in. Round your answer to the nearest tenth of a cubic inch.
Answer: in 
^(3)

Find the volume of a right circular cone that has a height of 22.11 in\text{in} and a base with a diameter of 44.88 in\text{in}. Round your answer to the nearest tenth of a cubic inch.\newlineAnswer: in\text{in} 3 ^{3}

Full solution

Q. Find the volume of a right circular cone that has a height of 22.11 in\text{in} and a base with a diameter of 44.88 in\text{in}. Round your answer to the nearest tenth of a cubic inch.\newlineAnswer: in\text{in} 3 ^{3}
  1. Find Radius of Base: To find the volume of a cone, we use the formula V=(13)πr2hV = (\frac{1}{3})\pi r^2 h, where rr is the radius of the base and hh is the height of the cone. First, we need to find the radius of the base. The diameter is given as 4.84.8 inches, so the radius is half of that.\newlineRadius, r=Diameter/2=4.8 inches/2=2.4 inches.r = \text{Diameter} / 2 = 4.8 \text{ inches} / 2 = 2.4 \text{ inches}.
  2. Plug Values into Formula: Now we can plug the values of the radius and height into the volume formula.\newlineV=13πr2hV = \frac{1}{3}\pi r^2 h\newlineV=13π(2.4inches)2(2.1inches)V = \frac{1}{3}\pi (2.4 \, \text{inches})^2(2.1 \, \text{inches})
  3. Calculate Radius Squared: Next, we calculate the radius squared and then multiply by the height.\newline(2.4 inches)2=5.76 inches2(2.4 \text{ inches})^2 = 5.76 \text{ inches}^2\newlineV=13π(5.76 inches2)(2.1 inches)V = \frac{1}{3}\pi(5.76 \text{ inches}^2)(2.1 \text{ inches})
  4. Multiply Radius Squared by Height: Now we multiply 5.76inches25.76\,\text{inches}^2 by 2.1inches2.1\,\text{inches}.\newlineV=(13)π(5.76inches2×2.1inches)V = \left(\frac{1}{3}\right)\pi\left(5.76\,\text{inches}^2 \times 2.1\,\text{inches}\right)\newlineV=(13)π(12.096inches3)V = \left(\frac{1}{3}\right)\pi\left(12.096\,\text{inches}^3\right)
  5. Find Volume: Finally, we multiply by π\pi and divide by 33 to find the volume.\newlineV=(13)π(12.096 inches3)V = \left(\frac{1}{3}\right)\pi(12.096 \text{ inches}^3)\newlineV(13)(3.14159)(12.096 inches3)V \approx \left(\frac{1}{3}\right)(3.14159)(12.096 \text{ inches}^3)\newlineV12.732 inches3V \approx 12.732 \text{ inches}^3
  6. Round to Nearest Tenth: Now we round the volume to the nearest tenth of a cubic inch.\newlineV12.7V \approx 12.7 inches3^3

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