Find the volume of a right circular cone that has a height of 9.2ft and a base with a circumference of 7.6ft. Round your answer to the nearest tenth of a cubic foot. Answer: ft^(3)

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Find the volume of a right circular cone that has a height of  9.2ft and a base with a circumference of  7.6ft. Round your answer to the nearest tenth of a cubic foot. Answer:  ft^(3)

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Find Radius of Base: First, we need to find the radius of the base of the cone. The formula for the circumference (C) of a circle is C = 2πr, where r is the radius. We can rearrange this formula to solve for r: r = C / (2π). Given that the circumference is 7.6 feet, we can calculate the radius as follows: r = 7.6 ft / (2π)Calculate Radius: Now, let's calculate the radius using the value of π as approximately 3.14159. r = 7.6 ft / (2 * 3.14159) r ≈ 7.6 ft / 6.28318 r ≈ 1.21 ft We will round to two decimal places for intermediate calculations to maintain accuracy.Calculate Volume: Next, we use the formula for the volume (V) of a cone, which is V = (1/3)πr^2h, where r is the radius and h is the height of the cone. We have r ≈ 1.21 ft and h = 9.2 ft. Plugging these values into the formula gives us: V = (1/3)π(1.21 ft)^2(9.2 ft)Volume Calculation: Now we calculate the volume: V ≈ (1/3) * 3.14159 * (1.21 ft)^2 * 9.2 ft V ≈ (1/3) * 3.14159 * 1.4641 ft^2 * 9.2 ft V ≈ 0.46453 * 3.14159 * 13.4692 ft^3 V ≈ 19.625 ft^3Round Volume: Finally, we round the volume to the nearest tenth of a cubic foot as requested. V ≈ 19.6 ft^3

Find the volume of a right circular cone that has a height of $9.2 \mathrm{ft}$ and a base with a circumference of $7.6 \mathrm{ft}$ . Round your answer to the nearest tenth of a cubic foot. $\newline$ Answer: $\mathrm{ft}^{3}$

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Find the volume of a right circular cone that has a height of 9.2ft 9.2 \mathrm{ft} 9.2ft and a base with a circumference of 7.6ft 7.6 \mathrm{ft} 7.6ft. Round your answer to the nearest tenth of a cubic foot.\newlineAnswer: ft3 \mathrm{ft}^{3} ft3

Find the volume of a right circular cone that has a height of $9.2 \mathrm{ft}$ and a base with a circumference of $7.6 \mathrm{ft}$ . Round your answer to the nearest tenth of a cubic foot. $\newline$ Answer: $\mathrm{ft}^{3}$