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Find the volume of a pyramid with a square base, where the side length of the base is 10.6 in and the height of the pyramid is 
14.9in. Round your answer to the nearest tenth of a cubic inch.
Answer: in 
^(3)

Find the volume of a pyramid with a square base, where the side length of the base is 1010.66 in\text{in} and the height of the pyramid is 14.9 14.9 in\mathrm{in} . Round your answer to the nearest tenth of a cubic inch.\newlineAnswer: in\text{in} 3 ^{3}

Full solution

Q. Find the volume of a pyramid with a square base, where the side length of the base is 1010.66 in\text{in} and the height of the pyramid is 14.9 14.9 in\mathrm{in} . Round your answer to the nearest tenth of a cubic inch.\newlineAnswer: in\text{in} 3 ^{3}
  1. Formula Explanation: The formula to find the volume of a pyramid with a square base is V=(13)×base_area×heightV = (\frac{1}{3}) \times \text{base\_area} \times \text{height}. The base_area\text{base\_area} for a square is found by squaring the side length of the base.
  2. Calculate Base Area: First, calculate the area of the base by squaring the side length of the base, which is 10.610.6 inches.base_area=side_length2=10.62=112.36 in2\text{base\_area} = \text{side\_length}^2 = 10.6^2 = 112.36 \text{ in}^2
  3. Volume Formula: Next, use the volume formula with the base area and the height of the pyramid, which is 14.914.9 inches.V=(13)×base_area×height=(13)×112.36 in2×14.9 inV = \left(\frac{1}{3}\right) \times \text{base\_area} \times \text{height} = \left(\frac{1}{3}\right) \times 112.36 \text{ in}^2 \times 14.9 \text{ in}
  4. Perform Calculation: Now, perform the multiplication and division to find the volume. V=(13)×112.36×14.937.4533×14.9558.0547in3V = (\frac{1}{3}) \times 112.36 \times 14.9 \approx 37.4533 \times 14.9 \approx 558.0547 \, \text{in}^3
  5. Round Volume: Finally, round the volume to the nearest tenth of a cubic inch. V558.1in3V \approx 558.1 \, \text{in}^3

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