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Find the volume of a pyramid with a square base, where the side length of the base is 18.2 in and the height of the pyramid is 12.2in. Round your answer to the nearest tenth of a cubic inch. Answer: in ^(3)

Find the volume of a pyramid with a square base, where the side length of the base is 1818.22 in and the height of the pyramid is 12.2in 12.2 \mathrm{in} . Round your answer to the nearest tenth of a cubic inch.\newlineAnswer: in 3 ^{3}

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Q. Find the volume of a pyramid with a square base, where the side length of the base is 1818.22 in and the height of the pyramid is 12.2in 12.2 \mathrm{in} . Round your answer to the nearest tenth of a cubic inch.\newlineAnswer: in 3 ^{3}
  1. Calculate Base Area: The formula to calculate the volume of a pyramid with a square base is V=13×base_area×heightV = \frac{1}{3} \times \text{base\_area} \times \text{height}. The base area of a square is found by squaring the side length. Let's calculate the base area first.\newlineBase area = side_length2=18.2 in×18.2 in=331.24 in2\text{side\_length}^2 = 18.2 \, \text{in} \times 18.2 \, \text{in} = 331.24 \, \text{in}^2
  2. Find Volume: Now, we will use the base area to find the volume of the pyramid. Volume = (13)×base_area×height=(13)×331.24 in2×12.2 in(\frac{1}{3}) \times \text{base\_area} \times \text{height} = (\frac{1}{3}) \times 331.24 \, \text{in}^2 \times 12.2 \, \text{in}
  3. Perform Multiplication and Division: Let's perform the multiplication and division to find the volume.\newlineVolume = (13)×331.24 in2×12.2 in=110.4133 in2×12.2 in≈1346.04246 in3(\frac{1}{3}) \times 331.24 \, \text{in}^2 \times 12.2 \, \text{in} = 110.4133 \, \text{in}^2 \times 12.2 \, \text{in} \approx 1346.04246 \, \text{in}^3
  4. Round Volume: Finally, we need to round the volume to the nearest tenth of a cubic inch.\newlineRounded volume ≈1346.0 in3\approx 1346.0 \, \text{in}^3

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