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Find the volume of a pyramid with a square base, where the perimeter of the base is 
4.2ft and the height of the pyramid is 
4.7ft. Round your answer to the nearest tenth of a cubic foot.
Answer: 
ft^(3)

Find the volume of a pyramid with a square base, where the perimeter of the base is 4.2ft 4.2 \mathrm{ft} and the height of the pyramid is 4.7ft 4.7 \mathrm{ft} . Round your answer to the nearest tenth of a cubic foot.\newlineAnswer: ft3 \mathrm{ft}^{3}

Full solution

Q. Find the volume of a pyramid with a square base, where the perimeter of the base is 4.2ft 4.2 \mathrm{ft} and the height of the pyramid is 4.7ft 4.7 \mathrm{ft} . Round your answer to the nearest tenth of a cubic foot.\newlineAnswer: ft3 \mathrm{ft}^{3}
  1. Find Side Length: To find the volume of a pyramid with a square base, we need to know the length of a side of the base square and the height of the pyramid. The formula for the volume of a pyramid is V=(13)×base area×heightV = (\frac{1}{3}) \times \text{base area} \times \text{height}. First, we need to find the length of a side of the base square using the perimeter.\newlineThe perimeter (PP) of a square is given by P=4×side length(s)P = 4 \times \text{side length} (s). Given P=4.2P = 4.2 feet, we can solve for ss.\newlines=P4s = \frac{P}{4}\newlines=4.2 ft4s = \frac{4.2 \text{ ft}}{4}\newlines=1.05 fts = 1.05 \text{ ft}
  2. Calculate Base Area: Now that we have the length of a side of the base square, we can find the area of the base AA. The area of a square is given by A=s2A = s^2. A=(1.05ft)2A = (1.05 \, \text{ft})^2 A=1.1025ft2A = 1.1025 \, \text{ft}^2
  3. Calculate Volume: With the base area and the height of the pyramid known, we can now calculate the volume VV.
    V=13×base area×heightV = \frac{1}{3} \times \text{base area} \times \text{height}
    V=13×1.1025ft2×4.7ftV = \frac{1}{3} \times 1.1025 \, \text{ft}^2 \times 4.7 \, \text{ft}
    V=0.3675ft2×4.7ftV = 0.3675 \, \text{ft}^2 \times 4.7 \, \text{ft}
    V=1.72725ft3V = 1.72725 \, \text{ft}^3
  4. Round Final Answer: Finally, we round the answer to the nearest tenth of a cubic foot. V1.7ft3V \approx 1.7 \, \text{ft}^3

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