Find the volume of a pyramid with a square base, where the area of the base is 7.7m^(2) and the height of the pyramid is 4.2m. Round your answer to the nearest tenth of a cubic meter. Answer: m^(3)

Formula Application: To find the volume of a pyramid with a square base, we use the formula: Volume = (Base Area × Height) / 3 Given that the area of the base (A) is 7.7m^2 and the height (h) is 4.2m, we can substitute these values into the formula.Substitution: Now, let's plug in the values and calculate the volume: Volume = (7.7m^2 × 4.2m) / 3Multiplication: Perform the multiplication of the base area and the height: Volume = (32.34m^3) / 3Division and Rounding: Finally, divide by 3 to find the volume: Volume = 32.34m^3 / 3 ≈ 10.78m^3 Since we need to round to the nearest tenth, the volume is approximately 10.8m^3.

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Find the volume of a pyramid with a square base, where the area of the base is
7.7m^(2) and the height of the pyramid is
4.2m. Round your answer to the nearest tenth of a cubic meter.
Answer:
m^(3)

Find the volume of a pyramid with a square base, where the area of the base is $7.7 \mathrm{~m}^{2}$ and the height of the pyramid is $4.2 \mathrm{~m}$ . Round your answer to the nearest tenth of a cubic meter. $\newline$ Answer: $\mathrm{m}^{3}$

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Evaluate variable expressions: word problems

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Q. Find the volume of a pyramid with a square base, where the area of the base is

7.7 \mathrm{~m}^{2}

and the height of the pyramid is

4.2 \mathrm{~m}

. Round your answer to the nearest tenth of a cubic meter.

\newline

Answer:

\mathrm{m}^{3}

Formula Application: To find the volume of a pyramid with a square base, we use the formula: $\newline$ Volume = $(\text{Base Area} \times \text{Height}) / 3$ $\newline$ Given that the area of the base $A$ is $7.7\text{m}^2$ and the height $h$ is $4.2\text{m}$ , we can substitute these values into the formula.
Substitution: Now, let's plug in the values and calculate the volume: $\newline$ Volume = $(7.7\,\text{m}^2 \times 4.2\,\text{m}) / 3$
Multiplication: Perform the multiplication of the base area and the height: $\text{Volume} = \frac{32.34\,\text{m}^3}{3}$
Division and Rounding: Finally, divide by $3$ to find the volume: $\newline$ Volume = $\frac{32.34m^3}{3} \approx 10.78m^3$ $\newline$ Since we need to round to the nearest tenth, the volume is approximately $10.8m^3$ .