Find the volume of a pyramid with a square base, where the area of the base is 6.9ft^(2) and the height of the pyramid is 3.1ft. Round your answer to the nearest tenth of a cubic foot. Answer: ft^(3)

Recall Volume Formula: Recall the formula for the volume of a pyramid with a square base. The formula for the volume V of a pyramid with a square base is V = (1/3) × base area × height.Plug in Values: Plug in the given values for the base area and height into the volume formula. The base area A is given as 6.9 square feet and the height h is given as 3.1 feet. So, V = (1/3) × 6.9 ft² × 3.1 ft.Calculate Volume: Calculate the volume using the values from Step 2. V = (1/3) × 6.9 ft² × 3.1 ft = (1/3) × 21.39 ft³ = 7.13 ft³.Round Answer: Round the answer to the nearest tenth of a cubic foot. The calculated volume is 7.13 ft³, which is already to the nearest tenth, so rounding is not necessary.

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Find the volume of a pyramid with a square base, where the area of the base is
6.9ft^(2) and the height of the pyramid is
3.1ft. Round your answer to the nearest tenth of
a cubic foot.
Answer:
ft^(3)

Find the volume of a pyramid with a square base, where the area of the base is $6.9 \mathrm{ft}^{2}$ and the height of the pyramid is $3.1 \mathrm{ft}$ . Round your answer to the nearest tenth of $a$ cubic foot. $\newline$ Answer: $\mathrm{ft}^{3}$

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Math Problems

Grade 6

Evaluate variable expressions: word problems

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Q. Find the volume of a pyramid with a square base, where the area of the base is

6.9 \mathrm{ft}^{2}

and the height of the pyramid is

3.1 \mathrm{ft}

. Round your answer to the nearest tenth of

a

cubic foot.

\newline

Answer:

\mathrm{ft}^{3}

Recall Volume Formula: Recall the formula for the volume of a pyramid with a square base. The formula for the volume $V$ of a pyramid with a square base is $V = \frac{1}{3} \times \text{base area} \times \text{height}$ .
Plug in Values: Plug in the given values for the base area and height into the volume formula. $\newline$ The base area $A$ is given as $6.9$ square feet and the height $h$ is given as $3.1$ feet. $\newline$ So, $V = (\frac{1}{3}) \times 6.9 \text{ ft}^2 \times 3.1 \text{ ft}$ .
Calculate Volume: Calculate the volume using the values from Step $2$ . $\newline$ $V = \frac{1}{3} \times 6.9 \, \text{ft}^2 \times 3.1 \, \text{ft} = \frac{1}{3} \times 21.39 \, \text{ft}^3 = 7.13 \, \text{ft}^3$ .
Round Answer: Round the answer to the nearest tenth of a cubic foot. The calculated volume is $7.13\,\text{ft}^3$ , which is already to the nearest tenth, so rounding is not necessary.