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Find the value of the following expression and round to the nearest integer:

sum_(n=2)^(34)30(1.3)^(n-2)
Answer:

Find the value of the following expression and round to the nearest integer:\newlinen=23430(1.3)n2 \sum_{n=2}^{34} 30(1.3)^{n-2} \newlineAnswer:

Full solution

Q. Find the value of the following expression and round to the nearest integer:\newlinen=23430(1.3)n2 \sum_{n=2}^{34} 30(1.3)^{n-2} \newlineAnswer:
  1. Given series and terms: We are given a geometric series with the first term a=30(1.3)22=30(1)=30a = 30(1.3)^{2-2} = 30(1) = 30 and a common ratio r=1.3r = 1.3. The sum of a finite geometric series can be found using the formula Sn=a(1rn)(1r)S_n = \frac{a(1 - r^n)}{(1 - r)}, where nn is the number of terms. First, we need to find the number of terms in the series.
  2. Number of terms calculation: The series starts at n=2n=2 and ends at n=34n=34, so the number of terms is 342+1=3334 - 2 + 1 = 33. Now we can use the formula for the sum of a geometric series.
  3. Formula for sum of geometric series: Plugging the values into the formula, we get S33=30(11.333)/(11.3)S_{33} = 30(1 - 1.3^{33}) / (1 - 1.3). We need to calculate 1.3331.3^{33} and then proceed with the formula.
  4. Calculate 1.3331.3^{33}: Using a calculator, we find that 1.3331.3^{33} is approximately 1425.76311425.7631. Now we substitute this value into the formula.
  5. Substitute values into formula: Substituting the values, we get S33=30(11425.7631)(11.3)=30(1424.7631)(0.3)S_{33} = \frac{30(1 - 1425.7631)}{(1 - 1.3)} = \frac{30(-1424.7631)}{(-0.3)}. We simplify this to get the sum.
  6. Simplify expression for sum: Simplifying the expression, we get S33=30×1424.7631/0.3S_{33} = 30 \times 1424.7631 / 0.3. Performing the division and multiplication, we find the sum.
  7. Perform division and multiplication: The sum S33S_{33} is approximately 30×4749.2103=142476.30930 \times 4749.2103 = 142476.309. Now we round this to the nearest integer.
  8. Round sum to nearest integer: Rounding 142476.309142476.309 to the nearest integer, we get 142476142476.

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