Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the value of the following expression and round to the nearest integer:

sum_(n=2)^(50)50(1.12)^(n-2)
Answer:

Find the value of the following expression and round to the nearest integer:\newlinen=25050(1.12)n2 \sum_{n=2}^{50} 50(1.12)^{n-2} \newlineAnswer:

Full solution

Q. Find the value of the following expression and round to the nearest integer:\newlinen=25050(1.12)n2 \sum_{n=2}^{50} 50(1.12)^{n-2} \newlineAnswer:
  1. Recognize Geometric Series: Recognize that the given expression is a geometric series. A geometric series has the form n=0Narn\sum_{n=0}^{N} ar^n, where aa is the first term, rr is the common ratio, and NN is the number of terms. In this case, the first term is 50(1.12)0=5050(1.12)^0 = 50, the common ratio rr is 1.121.12, and the series starts at n=2n=2 and goes to n=50n=50.
  2. Adjust Series Starting Point: Adjust the series to start at n=0n=0 for easier calculation. To do this, we can factor out the term (1.12)2(1.12)^2 from each term in the series, which gives us 50(1.12)0+50(1.12)1++50(1.12)4850(1.12)^0 + 50(1.12)^1 + \ldots + 50(1.12)^{48}. Now the series starts at n=0n=0 and goes to n=48n=48.
  3. Use Finite Series Formula: Use the formula for the sum of a finite geometric series, which is S=a(1rN)/(1r)S = a(1 - r^N) / (1 - r), where SS is the sum of the series, aa is the first term, rr is the common ratio, and NN is the number of terms. Here, a=50a = 50, r=1.12r = 1.12, and N=49N = 49 (since we start at n=0n=0 and go to n=48n=48, which is SS00 terms).
  4. Calculate Sum Formula: Plug the values into the formula to find the sum of the series.\newlineS=50(11.1249)11.12S = \frac{50(1 - 1.12^{49})}{1 - 1.12}
  5. Calculate 1.12491.12^{49}: Calculate the sum using the values from Step 44.\newlineS=50(11.1249)/(11.12)S = 50(1 - 1.12^{49}) / (1 - 1.12)\newlineS=50(11.1249)/(0.12)S = 50(1 - 1.12^{49}) / (-0.12)\newlineS=50(11.1249)/0.12S = -50(1 - 1.12^{49}) / 0.12
  6. Substitute Value in Formula: Calculate 1.12491.12^{49} using a calculator to ensure accuracy.\newline1.1249289.681.12^{49} \approx 289.68 (rounded to two decimal places for simplicity)
  7. Perform Multiplication and Division: Substitute the value from Step 66 into the sum formula.\newlineS=50(1289.68)/0.12S = -50(1 - 289.68) / 0.12\newlineS=50(288.68)/0.12S = -50(-288.68) / 0.12
  8. Find Final Sum: Perform the multiplication and division to find the sum.\newlineS=50×288.68/0.12S = 50 \times 288.68 / 0.12\newlineS50×2405.67S \approx 50 \times 2405.67\newlineS120283.33S \approx 120283.33
  9. Round to Nearest Integer: Round the sum to the nearest integer. S120283S \approx 120283

More problems from Sum of finite series starts from 1