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Find the sum of the infinite geometric series.\newline9+274+8116+24364+9 + \frac{27}{4} + \frac{81}{16} + \frac{243}{64} + \newlineWrite your answer as an integer or a fraction in simplest form.\newline______

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Q. Find the sum of the infinite geometric series.\newline9+274+8116+24364+9 + \frac{27}{4} + \frac{81}{16} + \frac{243}{64} + \newlineWrite your answer as an integer or a fraction in simplest form.\newline______
  1. Identify first term and common ratio: First, we need to identify the first term aa and the common ratio rr of the geometric series.\newlineThe first term aa is the first number in the series, which is 99.\newlineThe common ratio rr is found by dividing the second term by the first term, which is 274/9\frac{27}{4} / 9.
  2. Calculate common ratio: Now, let's calculate the common ratio rr.r=274/9r = \frac{27}{4} / 9r=274×19r = \frac{27}{4} \times \frac{1}{9}r=2736r = \frac{27}{36}r=34r = \frac{3}{4}
  3. Use formula for infinite series: Since we have an infinite geometric series, we can use the formula for the sum of an infinite geometric series, which is S=a(1r)S = \frac{a}{(1 - r)}, provided that the absolute value of rr is less than 11. Here, r=34|r| = |\frac{3}{4}|, which is less than 11, so we can use the formula.
  4. Apply formula to find sum: Let's apply the formula to find the sum SS.S=a1rS = \frac{a}{1 - r}S=9134S = \frac{9}{1 - \frac{3}{4}}S=94434S = \frac{9}{\frac{4}{4} - \frac{3}{4}}S=914S = \frac{9}{\frac{1}{4}}S=9×41S = 9 \times \frac{4}{1}S=36S = 36

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