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Find the sum of the infinite geometric series.\newline7+214+6316+18964+7 + \frac{21}{4} + \frac{63}{16} + \frac{189}{64} + \dots\newlineWrite your answer as an integer or a fraction in simplest form.\newline______

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Q. Find the sum of the infinite geometric series.\newline7+214+6316+18964+7 + \frac{21}{4} + \frac{63}{16} + \frac{189}{64} + \dots\newlineWrite your answer as an integer or a fraction in simplest form.\newline______
  1. Identify first term and common ratio: First, we need to identify the first term aa and the common ratio rr of the geometric series.\newlineThe first term aa is the first number in the series, which is 77.\newlineTo find the common ratio rr, we divide the second term by the first term.\newliner=214/7r = \frac{21}{4} / 7\newliner=214×7r = \frac{21}{4 \times 7}\newliner=2128r = \frac{21}{28}\newliner=34r = \frac{3}{4}
  2. Calculate common ratio: Now that we have the first term a=7a = 7 and the common ratio r=34r = \frac{3}{4}, we can use the formula for the sum of an infinite geometric series, which is S=a1rS = \frac{a}{1 - r}, provided that |r| < 1.\newlineIn this case, |\frac{3}{4}| < 1, so we can use the formula.\newlineS=7134S = \frac{7}{1 - \frac{3}{4}}
  3. Use formula for sum: Next, we calculate the sum using the formula.\newlineS=7134S = \frac{7}{1 - \frac{3}{4}}\newlineS=74434S = \frac{7}{\frac{4}{4} - \frac{3}{4}}\newlineS=714S = \frac{7}{\frac{1}{4}}\newlineS=7×41S = 7 \times \frac{4}{1}\newlineS=28S = 28

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