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Find the sum of the infinite geometric series.\newline63238332+-6 - \frac{3}{2} - \frac{3}{8} - \frac{3}{32} + \newlineWrite your answer as an integer or a fraction in simplest form.\newline______

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Q. Find the sum of the infinite geometric series.\newline63238332+-6 - \frac{3}{2} - \frac{3}{8} - \frac{3}{32} + \newlineWrite your answer as an integer or a fraction in simplest form.\newline______
  1. Identify first term and common ratio: First, we need to identify the first term aa and the common ratio rr of the geometric series.\newlineThe first term aa is 6-6.\newlineTo find the common ratio rr, we divide the second term by the first term: r=3/26=14r = \frac{-3/2}{-6} = \frac{1}{4}.
  2. Calculate common ratio: Now that we have the first term and the common ratio, we can use the formula for the sum of an infinite geometric series, which is S=a(1r)S = \frac{a}{(1 - r)}, provided that |r| < 1. In this case, |\frac{1}{4}| < 1, so we can use the formula.
  3. Use formula for sum: Let's plug the values into the formula: S=6114S = \frac{-6}{1 - \frac{1}{4}}.
  4. Plug values into formula: Now we calculate the denominator: 114=4414=341 - \frac{1}{4} = \frac{4}{4} - \frac{1}{4} = \frac{3}{4}.
  5. Calculate denominator: Next, we calculate the sum: S=(6)/(34)S = (-6) / (\frac{3}{4}). To divide by a fraction, we multiply by its reciprocal: S=(6)×(43)S = (-6) \times (\frac{4}{3}).
  6. Calculate sum: Now we perform the multiplication: S=243S = \frac{-24}{3}.
  7. Simplify fraction: Finally, we simplify the fraction: S=8S = -8.

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