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Find the sum of the infinite geometric series.\newline1+23+49+827+1 + \frac{2}{3} + \frac{4}{9} + \frac{8}{27} + \dots\newlineWrite your answer as an integer or a fraction in simplest form.\newline______

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Q. Find the sum of the infinite geometric series.\newline1+23+49+827+1 + \frac{2}{3} + \frac{4}{9} + \frac{8}{27} + \dots\newlineWrite your answer as an integer or a fraction in simplest form.\newline______
  1. Identify first term and common ratio: First, we need to identify the first term aa and the common ratio rr of the geometric series.\newlineThe first term aa is 11.\newlineThe common ratio rr is the factor by which each term is multiplied to get the next term. In this case, each term is multiplied by 23\frac{2}{3} to get the next term.\newlineSo, r=23r = \frac{2}{3}.
  2. Use formula for infinite series sum: To find the sum of an infinite geometric series, we use the formula S=a1rS = \frac{a}{1 - r}, where SS is the sum of the series, aa is the first term, and rr is the common ratio. This formula only works if the absolute value of rr is less than 11, which is true in this case since |\frac{2}{3}| < 1.
  3. Plug in values for calculation: Now we can plug the values of aa and rr into the formula to find the sum of the series.S=1123S = \frac{1}{1 - \frac{2}{3}}
  4. Calculate denominator of fraction: We calculate the denominator of the fraction: 123=3323=131 - \frac{2}{3} = \frac{3}{3} - \frac{2}{3} = \frac{1}{3}
  5. Find sum by dividing first term: Now we can find the sum SS by dividing the first term by the result we just found: S=1(1/3)S = \frac{1}{(1/3)}
  6. Multiply to get final sum: To divide by a fraction, we multiply by its reciprocal. So we multiply 11 by the reciprocal of 13\frac{1}{3}, which is 31\frac{3}{1} or just 33. \newlineS=1×3=3S = 1 \times 3 = 3

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