Q. Find the sum of the following series. Round to the nearest hundredth if necessary.5+15+45+…+7971615Sum of a finite geometric series:Sn=1−ra1−a1rn
Find Number of Terms: Next, we need to find the number of terms n in the series. We can do this by using the formula for the nth term of a geometric series, which is an=a1⋅r(n−1), where an is the nth term, a1 is the first term, and r is the common ratio. We will solve for n using the last term given, which is 7971615.7971615=5⋅3(n−1)
Isolate n in Equation: To solve for n, we need to isolate n on one side of the equation. We start by dividing both sides by 5.57971615=3(n−1)1594323=3(n−1)
Take Logarithm: Now, we take the logarithm of both sides to solve for n. We can use the natural logarithm or the common logarithm; here, we will use the natural logarithm for convenience.ln(1594323)=ln(3(n−1))
Rewrite Equation: Using the property of logarithms that ln(ab)=b×ln(a), we can rewrite the equation as:ln(1594323)=(n−1)×ln(3)
Solve for n−1: Now, we divide both sides by ln(3) to solve for n−1.(n−1)=ln(3)ln(1594323)
Calculate n−1: We calculate the value of n−1 using a calculator.n−1=ln(3)ln(1594323)≈14
Find n: To find n, we add 1 to the result.n=14+1n=15
Use Sum Formula: Now that we have the number of terms, we can use the formula for the sum of a finite geometric series to find the sum.Sn=1−ra1−a1⋅rn
Substitute Values: We substitute the values we know into the formula.S15=1−35−5×315
Calculate Numerator and Denominator: We calculate the numerator and the denominator separately.Numerator: 5−5×315Denominator: 1−3
Divide Numerator by Denominator: We calculate the numerator and the denominator using a calculator.Numerator: 5−5×315≈5−5×14348907≈5−71744535Denominator: 1−3=−2
Calculate Final Sum: Now we divide the numerator by the denominator to find the sum.S15=−25−71744535
Calculate Final Sum: Now we divide the numerator by the denominator to find the sum.S15=−25−71744535 We calculate the final sum using a calculator.S15=−2−71744530S15=35872265
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