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Find the sum of the first 9 terms of the following series, to the nearest integer.

22,44,88,dots
Answer:

Find the sum of the first 99 terms of the following series, to the nearest integer.\newline22,44,88, 22,44,88, \ldots \newlineAnswer:

Full solution

Q. Find the sum of the first 99 terms of the following series, to the nearest integer.\newline22,44,88, 22,44,88, \ldots \newlineAnswer:
  1. Identify type of series: Identify the type of series.\newlineThe given series is 22,44,88,22, 44, 88, \ldots, which appears to be a geometric series because each term is obtained by multiplying the previous term by a constant.
  2. Determine common ratio: Determine the common ratio rr of the series.\newlineTo find the common ratio, divide the second term by the first term.\newline4422=2\frac{44}{22} = 2\newlineCommon Ratio rr: 22
  3. Use formula for sum: Use the formula for the sum of the first nn terms of a geometric series.\newlineThe formula for the sum of the first nn terms (SnS_n) of a geometric series is:\newlineSn=a(1rn)/(1r)S_n = a \cdot (1 - r^n) / (1 - r), where aa is the first term and rr is the common ratio.
  4. Calculate sum of terms: Calculate the sum of the first 99 terms.\newlineFirst term (a)=22(a) = 22\newlineCommon ratio (r)=2(r) = 2\newlineNumber of terms (n)=9(n) = 9\newlineS9=22×(129)/(12)S_9 = 22 \times (1 - 2^9) / (1 - 2)
  5. Perform calculations: Perform the calculations.\newlineS9=22×(1512)/(12)S_9 = 22 \times (1 - 512) / (1 - 2)\newlineS9=22×(511)/(1)S_9 = 22 \times (-511) / (-1)\newlineS9=22×511S_9 = 22 \times 511\newlineS9=11242S_9 = 11242

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