Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the sum of the first 9 terms of the following sequence. Round to the nearest hundredth if necessary.

8,quad-4,quad2,dots
Sum of a finite geometric series:

S_(n)=(a_(1)-a_(1)r^(n))/(1-r)
Answer:

Find the sum of the first 99 terms of the following sequence. Round to the nearest hundredth if necessary.\newline8,4,2, 8, \quad-4, \quad 2, \ldots \newlineSum of a finite geometric series:\newlineSn=a1a1rn1r S_{n}=\frac{a_{1}-a_{1} r^{n}}{1-r} \newlineAnswer:

Full solution

Q. Find the sum of the first 99 terms of the following sequence. Round to the nearest hundredth if necessary.\newline8,4,2, 8, \quad-4, \quad 2, \ldots \newlineSum of a finite geometric series:\newlineSn=a1a1rn1r S_{n}=\frac{a_{1}-a_{1} r^{n}}{1-r} \newlineAnswer:
  1. Identify sequence type: First, we need to identify the type of sequence we are dealing with. The sequence 8,4,2,8, -4, 2, \ldots appears to be a geometric sequence because each term is obtained by multiplying the previous term by a common ratio. To find the common ratio (r)(r), we divide the second term by the first term.\newliner=(4)/8=1/2r = (-4) / 8 = -1/2
  2. Calculate common ratio: Next, we use the formula for the sum of the first nn terms of a geometric series, which is:\newlineSn=a1a1rn1rS_n = \frac{a_1 - a_1 \cdot r^n}{1 - r}\newlinewhere SnS_n is the sum of the first nn terms, a1a_1 is the first term, rr is the common ratio, and nn is the number of terms.
  3. Use sum formula: We plug in the values we know into the formula to find the sum of the first 99 terms:\newlinea1=8a_1 = 8 (the first term)\newliner=12r = -\frac{1}{2} (the common ratio)\newlinen=9n = 9 (the number of terms we want to sum)\newlineS9=88(12)91(12)S_9 = \frac{8 - 8 \cdot (-\frac{1}{2})^9}{1 - (-\frac{1}{2})}
  4. Calculate (12)9(-\frac{1}{2})^9: Now we calculate the value of (12)9(-\frac{1}{2})^9:\newline(12)9=1512(-\frac{1}{2})^9 = -\frac{1}{512}
  5. Substitute into formula: We substitute this value into the sum formula:\newlineS9=88×(1512)1(12)S_9 = \frac{8 - 8 \times (-\frac{1}{512})}{1 - (-\frac{1}{2})}\newlineS9=88×(1512)1+12S_9 = \frac{8 - 8 \times (-\frac{1}{512})}{1 + \frac{1}{2}}\newlineS9=8(164)32S_9 = \frac{8 - (-\frac{1}{64})}{\frac{3}{2}}
  6. Simplify expression: We simplify the expression:\newlineS9=8+16432S_9 = \frac{8 + \frac{1}{64}}{\frac{3}{2}}\newlineS9=51264+16432S_9 = \frac{\frac{512}{64} + \frac{1}{64}}{\frac{3}{2}}\newlineS9=5136432S_9 = \frac{\frac{513}{64}}{\frac{3}{2}}
  7. Divide by reciprocal: To divide by a fraction, we multiply by its reciprocal:\newlineS9=51364×23S_9 = \frac{513}{64} \times \frac{2}{3}\newlineS9=51396S_9 = \frac{513}{96}
  8. Simplify fraction: We simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 33: S9=17132S_9 = \frac{171}{32}
  9. Convert to decimal: Finally, we convert the fraction to a decimal to round to the nearest hundredth if necessary:\newlineS95.34375S_9 \approx 5.34375\newlineRounded to the nearest hundredth, S95.34S_9 \approx 5.34

More problems from Find trigonometric functions using a calculator