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Find the sum of the first 7 terms of the following sequence. Round to the nearest hundredth if necessary.

7,quad-35,quad175,dots
Sum of a finite geometric series:

S_(n)=(a_(1)-a_(1)r^(n))/(1-r)
Answer:

Find the sum of the first 77 terms of the following sequence. Round to the nearest hundredth if necessary.\newline7,35,175, 7, \quad-35, \quad 175, \ldots \newlineSum of a finite geometric series:\newlineSn=a1a1rn1r S_{n}=\frac{a_{1}-a_{1} r^{n}}{1-r} \newlineAnswer:

Full solution

Q. Find the sum of the first 77 terms of the following sequence. Round to the nearest hundredth if necessary.\newline7,35,175, 7, \quad-35, \quad 175, \ldots \newlineSum of a finite geometric series:\newlineSn=a1a1rn1r S_{n}=\frac{a_{1}-a_{1} r^{n}}{1-r} \newlineAnswer:
  1. Identify Terms: Identify the first term a1a_1 and the common ratio rr of the geometric sequence.\newlineThe first term a1a_1 is 77. To find the common ratio rr, we divide the second term by the first term: r=35/7=5r = -35 / 7 = -5.
  2. Use Formula: Use the formula for the sum of the first nn terms of a geometric series: Sn=a1a1rn1rS_n = \frac{a_1 - a_1 \cdot r^n}{1 - r}. Here, n=7n = 7, a1=7a_1 = 7, and r=5r = -5.
  3. Calculate Sum: Plug the values into the formula and calculate the sum. S7=(77(5)7)(1(5))S_7 = \frac{(7 - 7 \cdot (-5)^7)}{(1 - (-5))}
  4. Calculate Numerator: Calculate the numerator and the denominator separately.\newlineNumerator: 77×(5)7=77×(78125)=7+5468757 - 7 \times (-5)^7 = 7 - 7 \times (-78125) = 7 + 546875\newlineDenominator: 1(5)=1+5=61 - (-5) = 1 + 5 = 6
  5. Divide to Find Sum: Divide the numerator by the denominator to find the sum.\newlineS7=7+5468756S_7 = \frac{7 + 546875}{6}\newlineS7=5468826S_7 = \frac{546882}{6}\newlineS7=91147S_7 = 91147

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