Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the second derivative of the polynomial.\newlinef(x)=x2f(x) = -x^2\newlineWrite your answer as a polynomial in xx or as a constant. Simplify any fractions.\newlinef(x)=f''(x) = ______

Full solution

Q. Find the second derivative of the polynomial.\newlinef(x)=x2f(x) = -x^2\newlineWrite your answer as a polynomial in xx or as a constant. Simplify any fractions.\newlinef(x)=f''(x) = ______
  1. Find First Derivative: First, we need to find the first derivative of the polynomial f(x)=x2f(x) = -x^2. Using the power rule, which states that the derivative of xnx^n is nx(n1)n\cdot x^{(n-1)}, we apply it here:\newlinef(x)=ddx(x2)=2xf'(x) = \frac{d}{dx}(-x^2) = -2x
  2. Find Second Derivative: Next, we find the second derivative by differentiating f(x)=2xf'(x) = -2x once more. Again, using the power rule:\newlinef(x)=ddx(2x)=2f''(x) = \frac{d}{dx}(-2x) = -2

More problems from Find higher derivatives of polynomials