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Find the second derivative of the function.\newlinef(x)=−2xf(x) = -2^x\newlinef′′(x)=f''(x) = ______\_\_\_\_\_\_

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Q. Find the second derivative of the function.\newlinef(x)=−2xf(x) = -2^x\newlinef′′(x)=f''(x) = ______\_\_\_\_\_\_
  1. Identify Function: Identify the function to differentiate. f(x)=−2xf(x) = -2^x
  2. Calculate First Derivative: Calculate the first derivative using the chain rule.\newlinef′(x)=−2x⋅ln⁡(−2)f'(x) = -2^x \cdot \ln(-2)

More problems from Find second derivatives of trigonometric, exponential, and logarithmic functions

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f′(x)=12ex and f(4)=−16+12e4.f(0)= \begin{array}{l}f^{\prime}(x)=12 e^{x} \text { and } f(4)=-16+12 e^{4} . \\ f(0)=\end{array}
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The second derivative of the function f f is defined by f′′(x)=x2−5cos⁡(2x) f^{\prime \prime}(x)=x^{2}-5 \cos (2 x) for −2.5<x<3.5 -2.5<x<3.5 . Find the x x -values, if any, in the given domain where the function f f has an inflection point. You may use a calculator and round all values to 33 decimal places.\newlineAnswer: x= x=
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f′(x)=12ex and f(4)=−16+12e4.f(0)= \begin{array}{l}f^{\prime}(x)=12 e^{x} \text { and } f(4)=-16+12 e^{4} . \\ f(0)=\end{array}
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