Find the reference angle for a rotation of (4pi)/(11). Answer:

Understand reference angle: Understand the concept of a reference angle. A reference angle is the acute angle formed by the terminal side of an angle in standard position and the x-axis. It is always between 0 and π/2 radians (or 0 and 90 degrees) and is positive.Determine angle quadrant: Determine the quadrant in which the angle (4π)/(11) radians lies. Since (4π)/(11) is less than π (which is approximately 3.14), the angle lies in the first quadrant where the reference angle is the same as the angle itself.Calculate reference angle: Calculate the reference angle for (4π)/(11) radians when the angle is in the first quadrant. The reference angle θ' is equal to θ when θ is in the first quadrant. Therefore, θ' = (4π)/(11) radians.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the reference angle for a rotation of
(4pi)/(11).
Answer:

Find the reference angle for a rotation of $\frac{4 \pi}{11}$ . $\newline$ Answer: $\newline$

View step-by-step help

Home

Math Problems

Algebra 2

Inverses of csc, sec, and cot

Full solution

Q. Find the reference angle for a rotation of

\frac{4 \pi}{11}

\newline

Answer:

\newline

Understand reference angle: Understand the concept of a reference angle. A reference angle is the acute angle formed by the terminal side of an angle in standard position and the x-axis. It is always between $0$ and $\pi/2$ radians (or $0$ and $90$ degrees) and is positive.
Determine angle quadrant: Determine the quadrant in which the angle $(4\pi)/(11)$ radians lies. $\newline$ Since $(4\pi)/(11)$ is less than $\pi$ (which is approximately $3.14$ ), the angle lies in the first quadrant where the reference angle is the same as the angle itself.
Calculate reference angle: Calculate the reference angle for $(4\pi)/(11)$ radians when the angle is in the first quadrant. $\newline$ The reference angle $\theta'$ is equal to $\theta$ when $\theta$ is in the first quadrant. Therefore, $\theta' = (4\pi)/(11)$ radians.