Find the radius of the circle. x^(2)+y^(2)=36

Circle Standard Form: The equation of a circle in standard form is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius. The given equation is already in standard form with h = 0 and k = 0, which means the center is at the origin (0,0).Identify Radius: To find the radius, we compare the given equation x^2 + y^2 = 36 to the standard form equation and identify the value of r^2. In this case, r^2 = 36.Calculate Radius: To find the radius r, we take the square root of both sides of the equation r^2 = 36. The square root of 36 is 6, so r = 6.

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Find the radius of the circle. $\newline$ $x^{2}+y^{2}=36$

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Q. Find the radius of the circle.

\newline

x^{2}+y^{2}=36

Circle Standard Form: The equation of a circle in standard form is $(x - h)^2 + (y - k)^2 = r^2$ , where $(h, k)$ is the center of the circle and $r$ is the radius. The given equation is already in standard form with $h = 0$ and $k = 0$ , which means the center is at the origin $(0,0)$ .
Identify Radius: To find the radius, we compare the given equation $x^2 + y^2 = 36$ to the standard form equation and identify the value of $r^2$ . In this case, $r^2 = 36$ .
Calculate Radius: To find the radius $r$ , we take the square root of both sides of the equation $r^2 = 36$ . The square root of $36$ is $6$ , so $r = 6$ .