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Find the radius of a circle in which the central angle, 
alpha, intercepts an arc of the given length

alpha=60^(@),s=95" in "
The radius is 
◻ in.
(Round to the nearest hundredth as needed.)

Find the radius of a circle in which the central angle, α \alpha , intercepts an arc of the given length\newlineα=60,s=95 in  \alpha=60^{\circ}, \mathrm{s}=95 \text { in } \newlineThe radius is \square in.\newline(Round to the nearest hundredth as needed.)

Full solution

Q. Find the radius of a circle in which the central angle, α \alpha , intercepts an arc of the given length\newlineα=60,s=95 in  \alpha=60^{\circ}, \mathrm{s}=95 \text { in } \newlineThe radius is \square in.\newline(Round to the nearest hundredth as needed.)
  1. Identify Relationship: Identify the relationship between the arc length (ss), the radius (rr), and the central angle (α\alpha) in degrees.\newlineThe formula that relates these three variables is s=r×α×(π/180)s = r \times \alpha \times (\pi/180), where α\alpha is in degrees.
  2. Substitute Values: Substitute the given values into the formula.\newlineGiven that α=60\alpha = 60 degrees and s=95s = 95 inches, we can substitute these values into the formula to find the radius rr.\newline95=r×60×(π/180)95 = r \times 60 \times (\pi/180)
  3. Simplify Equation: Simplify the equation to solve for rr. First, simplify the right side of the equation by multiplying 6060 by π/180\pi/180, which simplifies to π/3\pi/3. 95=r×(π/3)95 = r \times (\pi/3) Now, to solve for rr, divide both sides of the equation by π/3\pi/3. r=95/(π/3)r = 95 / (\pi/3)
  4. Calculate Radius: Calculate the value of rr.r=95(π/3)=95×(3π)95×(33.14159)95×0.9549390.71835r = \frac{95}{(\pi/3)} = 95 \times (\frac{3}{\pi}) \approx 95 \times (\frac{3}{3.14159}) \approx 95 \times 0.95493 \approx 90.71835Round the result to the nearest hundredth.r90.72r \approx 90.72 inches

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