Find the product. 3*[[4,-2],[-1,4]]=

Understand the problem: Understand the problem. We need to multiply a scalar (the number 3) by a 2x2 matrix ([[4,-2],[-1,4]]). This means we will multiply each element of the matrix by the scalar.Multiply by scalar: Multiply each element of the matrix by the scalar. 3 * [[4,-2],[-1,4]] = [[3*4, 3*(-2)],[3*(-1), 3*4]]Perform multiplication: Perform the multiplication for each element. [[3*4, 3*(-2)],[3*(-1), 3*4]] = [[12, -6],[-3, 12]]

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Math Problems

Grade 6

Multiply two decimals: where does the decimal point go?

Full solution

Q. Find the product.

\newline

3 \cdot\left[\begin{array}{cc}4 & -2 \\ -1 & 4\end{array}\right]=

Understand the problem: Understand the problem. $\newline$ We need to multiply a scalar (the number $3$ ) by a $2 \times 2$ matrix ( $\left[\begin{array}{cc}4 & -2 \ -1 & 4\end{array}\right]$ ). This means we will multiply each element of the matrix by the scalar.
Multiply by scalar: Multiply each element of the matrix by the scalar. $\newline$ $3 \times \begin{bmatrix} 4 & -2 \ -1 & 4 \end{bmatrix} = \begin{bmatrix} 3\times 4, 3\times (-2) \ 3\times (-1), 3\times 4 \end{bmatrix}$
Perform multiplication: Perform the multiplication for each element. $\newline$ \left[\begin{array}{cc}3\times 4, & 3\times (-2)\3\times (-1), & 3\times 4\end{array}\right] = \left[\begin{array}{cc}12, & -6\-3, & 12\end{array}\right]