Find the numerical answer to the summation given below. sum_(n=2)^(66)(7n+6) Answer:

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Find the numerical answer to the summation given below.  sum_(n=2)^(66)(7n+6) Answer:

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Breakdown Summation: Recognize that the summation of a linear expression can be broken down into the summation of its individual terms. We can separate the given summation into two separate summations: one for the 7n term and one for the constant term 6. So, we rewrite the summation as: sum_(n=2)^(66)(7n) + sum_(n=2)^(66)(6)Evaluate First Term: Evaluate the first term sum_(n=2)^(66)(7n) using the summation rule for arithmetic series. The sum of an arithmetic series can be found using the formula: sum_(n=a)^(b)(dn) = d * (b(b+1)/2 - a(a-1)/2) where d is the common difference, a is the first term, and b is the last term. In our case, d = 7, a = 2, and b = 66. sum_(n=2)^(66)(7n) = 7 * (66(66+1)/2 - 2(2-1)/2)Calculate First Term: Calculate the first term sum_(n=2)^(66)(7n) using the formula from Step 2. sum_(n=2)^(66)(7n) = 7 * (66*67/2 - 2*1/2) = 7 * (2211 - 1) = 7 * 2210 = 15470Evaluate Second Term: Evaluate the second term sum_(n=2)^(66)(6) using the summation rule for a constant. The sum of a constant k from n=a to n=b is simply k(b-a+1). sum_(n=2)^(66)(6) = 6 * (66 - 2 + 1) = 6 * 65Calculate Second Term: Calculate the second term sum_(n=2)^(66)(6) using the calculation from Step 4. sum_(n=2)^(66)(6) = 6 * 65 = 390Find Total Sum: Add the results from Step 3 and Step 5 to find the total sum of the series. Total sum = 15470 + 390 = 15860

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=2}^{66}(7 n+6)$ $\newline$ Answer:

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Find the numerical answer to the summation given below.\newline∑n=266(7n+6) \sum_{n=2}^{66}(7 n+6) n=2∑66​(7n+6)\newlineAnswer:

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=2}^{66}(7 n+6)$ $\newline$ Answer: