Find the numerical answer to the summation given below. sum_(n=1)^(89)(2n+9) Answer:

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Find the numerical answer to the summation given below.  sum_(n=1)^(89)(2n+9) Answer:

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Recognize Arithmetic Series: Recognize that the series is an arithmetic series where each term can be written as an+ b, with a=2 and b=9. The sum of an arithmetic series can be found using the formula S = n/2 * (first term + last term), where n is the number of terms.Calculate First Term: Calculate the first term of the series by substituting n=1 into the expression (2n+9), which gives us 2(1)+9 = 11.Calculate Last Term: Calculate the last term of the series by substituting n=89 into the expression (2n+9), which gives us 2(89)+9 = 187.Calculate Number of Terms: Calculate the number of terms in the series. Since the series starts at n=1 and ends at n=89, there are 89 terms in total.Use Sum Formula: Use the arithmetic series sum formula to find the sum of the series: S = n/2 * (first term + last term). Substituting the values we have S = 89/2 * (11 + 187).Perform Calculations: Perform the calculations inside the parentheses first: 11 + 187 = 198.Multiply Number of Terms: Now multiply the number of terms, which is 89/2, by the sum of the first and last term, which is 198: S = 89/2 * 198.Find Sum of Series: Perform the multiplication to find the sum of the series: S = 44.5 * 198 = 8811.

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=1}^{89}(2 n+9)$ $\newline$ Answer:

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Find the numerical answer to the summation given below.\newline∑n=189(2n+9) \sum_{n=1}^{89}(2 n+9) n=1∑89​(2n+9)\newlineAnswer:

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=1}^{89}(2 n+9)$ $\newline$ Answer: