Find the numerical answer to the summation given below. sum_(n=0)^(69)(2n+9) Answer:

Find First Term: We need to find the sum of the arithmetic series where the nth term is given by the formula (2n+9). The series starts at n=0 and ends at n=69.Find Last Term: First, let's find the first term of the series when n=0. Plugging in n=0 into the formula (2n+9) gives us the first term a_1 = 2(0) + 9 = 9.Calculate Sum Formula: Next, let's find the last term of the series when n=69. Plugging in n=69 into the formula (2n+9) gives us the last term a_70 = 2(69) + 9 = 138 + 9 = 147.Plug in Values: The sum of an arithmetic series can be found using the formula S_n = n/2 * (a_1 + a_n), where n is the number of terms, a_1 is the first term, and a_n is the last term. Since we start at n=0 and go to n=69, there are 70 terms in total.Calculate Sum: Now we can plug the values into the sum formula: S_70 = 70/2 * (9 + 147) = 35 * 156.Calculating the sum gives us S_70 = 35 * 156 = 5460.

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Find the numerical answer to the summation given below.

sum_(n=0)^(69)(2n+9)
Answer:

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=0}^{69}(2 n+9)$ $\newline$ Answer:

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Algebra 2

Sum of finite series starts from 1

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Q. Find the numerical answer to the summation given below.

\newline

\sum_{n=0}^{69}(2 n+9)

\newline

Answer:

Find First Term: We need to find the sum of the arithmetic series where the $n$ th term is given by the formula $(2n+9)$ . The series starts at $n=0$ and ends at $n=69$ .
Find Last Term: First, let's find the first term of the series when $n=0$ . Plugging in $n=0$ into the formula $(2n+9)$ gives us the first term $a_1 = 2(0) + 9 = 9$ .
Calculate Sum Formula: Next, let's find the last term of the series when $n=69$ . Plugging in $n=69$ into the formula $(2n+9)$ gives us the last term $a_{70} = 2(69) + 9 = 138 + 9 = 147$ .
Plug in Values: The sum of an arithmetic series can be found using the formula $S_n = \frac{n}{2} * (a_1 + a_n)$ , where $n$ is the number of terms, $a_1$ is the first term, and $a_n$ is the last term. Since we start at $n=0$ and go to $n=69$ , there are $70$ terms in total.
Calculate Sum: Now we can plug the values into the sum formula: $S_{70} = \frac{70}{2} \times (9 + 147) = 35 \times 156$ .
Calculate Sum: Now we can plug the values into the sum formula: $S_{70} = \frac{70}{2} \times (9 + 147) = 35 \times 156$ . Calculating the sum gives us $S_{70} = 35 \times 156 = 5460$ .