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Find the numerical answer to the summation given below.

sum_(n=1)^(78)(7n+6)
Answer:

Find the numerical answer to the summation given below.\newlinen=178(7n+6) \sum_{n=1}^{78}(7 n+6) \newlineAnswer:

Full solution

Q. Find the numerical answer to the summation given below.\newlinen=178(7n+6) \sum_{n=1}^{78}(7 n+6) \newlineAnswer:
  1. Recognize Parts: Recognize that the summation of the series can be separated into two parts: the summation of 7n7n and the summation of 66. This gives us n=1787n+n=1786\sum_{n=1}^{78}7n + \sum_{n=1}^{78}6.
  2. Evaluate First Part: Evaluate the first part of the summation n=1787n\sum_{n=1}^{78} 7n. This is a sum of an arithmetic series, which can be calculated using the formula for the sum of the first nn terms of an arithmetic series: Sn=n2×(a1+an)S_n = \frac{n}{2} \times (a_1 + a_n), where a1a_1 is the first term and ana_n is the last term. In this case, a1=7×1a_1 = 7 \times 1 and an=7×78a_n = 7 \times 78.
  3. Calculate First Part: Calculate the sum of the first part using the formula from Step 22.\newlineSn=782×(7×1+7×78)S_n = \frac{78}{2} \times (7\times1 + 7\times78)\newline=39×(7+546)= 39 \times (7 + 546)\newline=39×553= 39 \times 553\newline=21567= 21567
  4. Evaluate Second Part: Evaluate the second part of the summation n=1786\sum_{n=1}^{78} 6. Since 66 is a constant, the sum is simply 6×786 \times 78.
  5. Calculate Second Part: Calculate the sum of the second part.\newline6×78=4686 \times 78 = 468
  6. Add Results: Add the results from Step 33 and Step 55 to get the final answer.21567+468=2203521567 + 468 = 22035

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