Find the numerical answer to the summation given below. sum_(n=6)^(98)(6n+4) Answer:

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Find the numerical answer to the summation given below.  sum_(n=6)^(98)(6n+4) Answer:

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Arithmetic Series Sum Formula: We need to find the sum of the arithmetic series from n=6 to n=98 for the expression (6n+4). The general formula for the sum of an arithmetic series is S = n/2 * (a_1 + a_n), where n is the number of terms, a_1 is the first term, and a_n is the last term.Find First Term a_1: First, we need to find the first term a_1 by substituting n=6 into the expression (6n+4). This gives us a_1 = 6*6 + 4 = 36 + 4 = 40.Find Last Term a_n: Next, we find the last term a_n by substituting n=98 into the expression (6n+4). This gives us a_n = 6*98 + 4 = 588 + 4 = 592.Determine Number of Terms: Now, we need to determine the number of terms n in the series. Since the series starts at n=6 and ends at n=98, and it's an arithmetic series with a common difference of 6, we can use the formula for the nth term of an arithmetic series: a_n = a_1 + (n-1)d, where d is the common difference. Rearranging the formula to solve for n gives us n = ((a_n - a_1)/d) + 1. Substituting the values we have, n = ((592 - 40)/6) + 1 = (552/6) + 1 = 92 + 1 = 93.Calculate Sum: Now we can use the sum formula for an arithmetic series: S = n/2 * (a_1 + a_n). Substituting the values we have, S = 93/2 * (40 + 592) = 46.5 * 632.Calculating the sum gives us S = 46.5 * 632 = 29388.

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=6}^{98}(6 n+4)$ $\newline$ Answer:

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Find the numerical answer to the summation given below.\newline∑n=698(6n+4) \sum_{n=6}^{98}(6 n+4) n=6∑98​(6n+4)\newlineAnswer:

Find the numerical answer to the summation given below. $\newline$ $\sum_{n=6}^{98}(6 n+4)$ $\newline$ Answer: