Q. Find the minimum value of the function f(x)=x2+9x+17.3 to the nearest hundredth.Answer:
Identify Coefficients: To find the minimum value of the quadratic function f(x)=x2+9x+17.3, we can complete the square or use the vertex formula for a parabola. The vertex form of a parabola is given by f(x)=a(x−h)2+k, where (h,k) is the vertex of the parabola. Since the coefficient of x2 is positive, the parabola opens upwards, and the vertex represents the minimum point.
Calculate Vertex Coordinates: First, we identify the coefficients a, b, and c in the standard form of the quadratic equation, which is f(x)=ax2+bx+c. Here, a=1, b=9, and c=17.3.
Find x-coordinate of Vertex: The x-coordinate of the vertex h can be found using the formula h=−2ab. Plugging in the values of a and b, we get h=−2×19=−29=−4.5.
Find y-coordinate of Vertex: Now, we will find the y-coordinate of the vertex k by plugging the value of h back into the function. So, k=f(−4.5)=(−4.5)2+9∗(−4.5)+17.3.
Calculate Minimum Value: Calculating k, we get k=20.25−40.5+17.3=−20.25+17.3=−2.95.
Determine Vertex of Parabola: Therefore, the vertex of the parabola is at the point (−4.5,−2.95), and since this is a parabola that opens upwards, the y-coordinate of the vertex represents the minimum value of the function.
Round to Nearest Hundredth: Rounding the minimum value to the nearest hundredth, we get −2.95 as the minimum value of the function f(x)=x2+9x+17.3.
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