Q. Find the minimum value of the function f(x)=x2−14x+41.3 to the nearest hundredth.Answer:
Identify Coefficients: To find the minimum value of the quadratic function f(x)=x2−14x+41.3, we can complete the square or use the vertex formula for a parabola. The vertex form of a parabola is given by f(x)=a(x−h)2+k, where (h,k) is the vertex of the parabola. Since the coefficient of x2 is positive, the parabola opens upwards, and the vertex represents the minimum point.
Calculate Vertex Coordinates: First, we identify the coefficients a, b, and c in the standard form of the quadratic function, which is f(x)=ax2+bx+c. Here, a=1, b=−14, and c=41.3.
Find x-coordinate of Vertex: The x-coordinate of the vertex h can be found using the formula h=−2ab. Plugging in the values of a and b, we get h=−2×1−14=214=7.
Find y-coordinate of Vertex: Now, we need to find the y-coordinate of the vertex k, which is the value of the function at x=h. We substitute x=7 into the function: f(7)=(7)2−14×(7)+41.3=49−98+41.3=−49+41.3=−7.7.
Determine Vertex Minimum: The vertex of the parabola is at the point (7,−7.7). Since this is a parabola that opens upwards, the y-coordinate of the vertex, −7.7, represents the minimum value of the function.
Round to Nearest Hundredth: We round the minimum value to the nearest hundredth, which gives us −7.70 as the final answer.
More problems from Find trigonometric functions using a calculator