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Find the minimum value of the function 
f(x)=x^(2)-14 x+41.3 to the nearest hundredth.
Answer:

Find the minimum value of the function f(x)=x214x+41.3 f(x)=x^{2}-14 x+41.3 to the nearest hundredth.\newlineAnswer:

Full solution

Q. Find the minimum value of the function f(x)=x214x+41.3 f(x)=x^{2}-14 x+41.3 to the nearest hundredth.\newlineAnswer:
  1. Identify Coefficients: To find the minimum value of the quadratic function f(x)=x214x+41.3f(x) = x^2 - 14x + 41.3, we can complete the square or use the vertex formula for a parabola. The vertex form of a parabola is given by f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. Since the coefficient of x2x^2 is positive, the parabola opens upwards, and the vertex represents the minimum point.
  2. Calculate Vertex Coordinates: First, we identify the coefficients aa, bb, and cc in the standard form of the quadratic function, which is f(x)=ax2+bx+cf(x) = ax^2 + bx + c. Here, a=1a = 1, b=14b = -14, and c=41.3c = 41.3.
  3. Find x-coordinate of Vertex: The x-coordinate of the vertex hh can be found using the formula h=b2ah = -\frac{b}{2a}. Plugging in the values of aa and bb, we get h=142×1=142=7h = -\frac{-14}{2 \times 1} = \frac{14}{2} = 7.
  4. Find y-coordinate of Vertex: Now, we need to find the y-coordinate of the vertex kk, which is the value of the function at x=hx = h. We substitute x=7x = 7 into the function: f(7)=(7)214×(7)+41.3=4998+41.3=49+41.3=7.7f(7) = (7)^2 - 14 \times (7) + 41.3 = 49 - 98 + 41.3 = -49 + 41.3 = -7.7.
  5. Determine Vertex Minimum: The vertex of the parabola is at the point (7,7.7)(7, -7.7). Since this is a parabola that opens upwards, the yy-coordinate of the vertex, 7.7-7.7, represents the minimum value of the function.
  6. Round to Nearest Hundredth: We round the minimum value to the nearest hundredth, which gives us 7.70-7.70 as the final answer.

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