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Find the minimum value of the function 
f(x)=2x^(2)-25.8 x+89.7 to the nearest hundredth.
Answer:

Find the minimum value of the function f(x)=2x225.8x+89.7 f(x)=2 x^{2}-25.8 x+89.7 to the nearest hundredth.\newlineAnswer:

Full solution

Q. Find the minimum value of the function f(x)=2x225.8x+89.7 f(x)=2 x^{2}-25.8 x+89.7 to the nearest hundredth.\newlineAnswer:
  1. Identify function type: Identify the type of function.\newlineThe function f(x)=2x225.8x+89.7f(x) = 2x^2 - 25.8x + 89.7 is a quadratic function in the form of f(x)=ax2+bx+cf(x) = ax^2 + bx + c, where aa, bb, and cc are constants.
  2. Determine parabola vertex: Determine the vertex of the parabola. Since the coefficient of x2x^2 is positive (a=2a = 2), the parabola opens upwards, and the vertex represents the minimum point of the function.
  3. Calculate x-coordinate: Calculate the x-coordinate of the vertex.\newlineThe x-coordinate of the vertex of a parabola given by f(x)=ax2+bx+cf(x) = ax^2 + bx + c is found using the formula b2a-\frac{b}{2a}.\newlineFor our function, a=2a = 2 and b=25.8b = -25.8, so we have:\newlinex=(25.8)/(22)=25.84=6.45x = -(-25.8) / (2 \cdot 2) = \frac{25.8}{4} = 6.45
  4. Calculate y-coordinate: Calculate the y-coordinate of the vertex.\newlineTo find the y-coordinate of the vertex (which is the minimum value of the function), we substitute x=6.45x = 6.45 into the function:\newlinef(6.45)=2(6.45)225.8(6.45)+89.7f(6.45) = 2(6.45)^2 - 25.8(6.45) + 89.7
  5. Perform calculations: Perform the calculations.\newlinef(6.45)=2(41.6025)25.8(6.45)+89.7f(6.45) = 2(41.6025) - 25.8(6.45) + 89.7\newlinef(6.45)=83.205166.41+89.7f(6.45) = 83.205 - 166.41 + 89.7\newlinef(6.45)=83.205+89.7f(6.45) = -83.205 + 89.7\newlinef(6.45)=6.495f(6.45) = 6.495
  6. Round to nearest hundredth: Round the result to the nearest hundredth.\newlineThe minimum value of the function to the nearest hundredth is 6.506.50.

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