Q. Find the minimum value of the function f(x)=2x2−25.8x+89.7 to the nearest hundredth.Answer:
Identify function type: Identify the type of function.The function f(x)=2x2−25.8x+89.7 is a quadratic function in the form of f(x)=ax2+bx+c, where a, b, and c are constants.
Determine parabola vertex: Determine the vertex of the parabola. Since the coefficient of x2 is positive (a=2), the parabola opens upwards, and the vertex represents the minimum point of the function.
Calculate x-coordinate: Calculate the x-coordinate of the vertex.The x-coordinate of the vertex of a parabola given by f(x)=ax2+bx+c is found using the formula −2ab.For our function, a=2 and b=−25.8, so we have:x=−(−25.8)/(2⋅2)=425.8=6.45
Calculate y-coordinate: Calculate the y-coordinate of the vertex.To find the y-coordinate of the vertex (which is the minimum value of the function), we substitute x=6.45 into the function:f(6.45)=2(6.45)2−25.8(6.45)+89.7
Perform calculations: Perform the calculations.f(6.45)=2(41.6025)−25.8(6.45)+89.7f(6.45)=83.205−166.41+89.7f(6.45)=−83.205+89.7f(6.45)=6.495
Round to nearest hundredth: Round the result to the nearest hundredth.The minimum value of the function to the nearest hundredth is 6.50.
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