Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the minimum value of the function 
f(x)=2x^(2)-22 x+53 to the nearest hundredth.
Answer:

Find the minimum value of the function f(x)=2x222x+53 f(x)=2 x^{2}-22 x+53 to the nearest hundredth.\newlineAnswer:

Full solution

Q. Find the minimum value of the function f(x)=2x222x+53 f(x)=2 x^{2}-22 x+53 to the nearest hundredth.\newlineAnswer:
  1. Calculate Vertex: To find the minimum value of the function f(x)=2x222x+53f(x)=2x^{2}-22x+53, which is a quadratic function, we can use the vertex formula. The vertex of a parabola given by f(x)=ax2+bx+cf(x)=ax^2+bx+c is at the point (h,k)(h, k), where h=b2ah = -\frac{b}{2a}. Since the coefficient of x2x^2 is positive (a=2a=2), the parabola opens upwards, and the vertex represents the minimum point.
  2. Find x-coordinate: First, we calculate the x-coordinate of the vertex hh using h=b2ah = -\frac{b}{2a}. Here, a=2a = 2 and b=22b = -22, so h=222×2=224=5.5h = -\frac{-22}{2 \times 2} = \frac{22}{4} = 5.5.
  3. Find y-coordinate: Next, we find the y-coordinate of the vertex kk by substituting x=hx = h into the function f(x)f(x). So, k=f(5.5)=2×(5.5)222×(5.5)+53k = f(5.5) = 2\times(5.5)^2 - 22\times(5.5) + 53.
  4. Perform calculation: Now we perform the calculation: k=2×(5.5)222×(5.5)+53=2×30.25121+53=60.5121+53=7.5k = 2\times(5.5)^2 - 22\times(5.5) + 53 = 2\times30.25 - 121 + 53 = 60.5 - 121 + 53 = -7.5.
  5. Minimum value: The minimum value of the function f(x)f(x) is the yy-coordinate of the vertex, which is k=7.5k = -7.5. To the nearest hundredth, this value is already in the correct form.

More problems from Find trigonometric functions using a calculator