Q. Find the minimum value of the function f(x)=2x2−22x+53 to the nearest hundredth.Answer:
Calculate Vertex: To find the minimum value of the function f(x)=2x2−22x+53, which is a quadratic function, we can use the vertex formula. The vertex of a parabola given by f(x)=ax2+bx+c is at the point (h,k), where h=−2ab. Since the coefficient of x2 is positive (a=2), the parabola opens upwards, and the vertex represents the minimum point.
Find x-coordinate: First, we calculate the x-coordinate of the vertex h using h=−2ab. Here, a=2 and b=−22, so h=−2×2−22=422=5.5.
Find y-coordinate: Next, we find the y-coordinate of the vertex k by substituting x=h into the function f(x). So, k=f(5.5)=2×(5.5)2−22×(5.5)+53.
Perform calculation: Now we perform the calculation: k=2×(5.5)2−22×(5.5)+53=2×30.25−121+53=60.5−121+53=−7.5.
Minimum value: The minimum value of the function f(x) is the y-coordinate of the vertex, which is k=−7.5. To the nearest hundredth, this value is already in the correct form.
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